To start up windows and boot the system to make sure no hackers or viruses are on windows so your computer does not get infected with a hacker or virus
hope this helps
The answer is: [B]: " 2 " .
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Explanation:
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Given the chemical equation:
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<u> ? </u> H₂ + O₂ → 2 H₂<span>O ;
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</span> → <span> We are asked, "What coefficient, if any — should be put in front of the: " H</span>₂ " ;
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(which is on the "left-hand side" side of the chemical equation given— the "reactants") ;
→ to get a balanced chemical equation?
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→ Let us examine the "right-hand side" of this chemical equation—the product(s). In this case, the "product" given is: " 2 H₂O " .
So, on the "right hand side", we have:
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1) 4 "H's" → {Two "H₂" 's = 2 * 2 = "4 H's"} ; <u><em>and</em></u>:
2) 2 "O's" → { Two "O's").
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So, the left-hand side should have:
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1) 4 "H's" ; <u><em>and</em></u>:
2) 2 "O's" ;
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Let us examine the left-hand side (the "reactants").
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" <u> ? </u><u /> H₂ + O₂ " ;
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On the left-hand side, we already have:
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1) " 2 O's " ; → one "O₂" = "2 O's" ; and:
2) "2 H's " ; → one "H<span>₂" .</span>
Now, we would need:
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A "<u>total of "4 H's</u>". Is there any number we could put as a coefficient on the other reactant, which happens to be: "H₂" ; to make a <u><em>total of</em></u> "4 H's" ?
{Note: There are only these TWO (2) reactants in this chemical equation.}.
→ The "H₂" ; as it stands alone, is insufficient—since that would be only "2 H's".
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→ Thus, we can rule out: "Answer choices: [A] and [D]."
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<u>Note</u>:
→ Choice [A]: "1" ; The coefficient, "1"; is generally not (never?) used; and basically would function as the same as:
→ Choice: [D]: "<span>no coefficient is needed".
</span>→ <span>Choices [A] & [D]: would leave us with only "2 H's" on the "reactants side" (i.e. "left-hand side of the equation"; and we need FOUR ("4 H's").
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Since we are given: "H</span>₂" ; what coefficient could we put in front of this to get: "4 H's" ? (4÷2 =2). So we could put a "2" in front of the "H₂" ; to get:
"4 H's". The coefficient, "2" , corresponds directly with:
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→ Answer choice: [B]: "2" .
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{ <u>NOTE</u>: The remaining answer choice, [C], which is, "3" ; is INCORRECT; since 3 "H₂'s" would be "6 H's" ; (since 3 * "2 H's" equal "6 H's") ; which is too many "H's" → We need <u>exactly</u> "4 H's".}.
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So, the correctly balanced equation is:
2 H₂ + O₂ → 2 H₂O ;
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→ The coefficient that goes before the "H₂" ; to make this chemical equation balanced, is: "2" .
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The correct answer is: [B]: "2" .
→ The coefficient that goes before the "H₂" is: "2" .
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Hope this answer—and {lengthy} explanation—is of help!
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Answer:
Assumption: Only 1 job can be taken at a time
This becomes a weighted job scheduling problem.
Suppose there are n jobs
Sort the jobs according to fj(finish time)
Define an array named arr to store max profit till that job
arr[0] = v1(value of 1st job)
For i>0. arr[i] = maximum of arr[i-1] (profit till the previous job) or wi(weight of ith job) + profit till the previous non-conflicting job
Final ans = arr[n-1]
The previous non-conflicting job here means the last job with end timeless than equal to the current job.
To find the previous non-conflicting job if we traverse the array linearly Complexity(search = O(n)) = O(n.n) = O(n^2)
else if we use a binary search to find the job Complexity((search = O(Logn)) = O(n.Log(n))
<span>A. Budget can’t include donations to charities.</span>
Answer:
A race condition is actually possible in this scenario.
Explanation:
A race condition is an undesirable situation that occurs when a device or system attempts to perform two or more operations at the same time. In order to prevent the race condition from occurring the operations must be done in the proper sequence to be done correctly.
Here is an example of the race condition: Let's assume the Current Balance of the shared bank account is $600. The husband's program calls the withdraw($100) function and accesses the Current Balance of $600. But right before it stores the new Current Balance, the wife's program calls function deposit($100) function and accesses the Current Balance of $600. At this point, the husband's program changes the shared variable Current Balance to $500, followed by the wife's program changing the Current Balance variable to $700. Based on calling both withdraw($100) and deposit($100) functions, the Current Balance should again be $600, but it is $700. Alternatively, the Current Balance could also have been $500.
To prevent the race condition from occurring, the solution will be to create a method to "Lock" on the Current Balance variable. Each method must "Lock" the variable before accessing it and changing it. If a method determines that the variable is "Locked," then it must wait before accessing it.
