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3 years ago

9y^2-6y+1=0 FIND Y PLEASE HELP STEP BY STEP

Mathematics

1 answer:

dlinn [17]3 years ago

4 0

Answer:

y = 1/3

Step-by-step explanation:

Step 1: Factor

9y^2 - 6y + 1 = 0

(3y - 1)(3y - 1) = 0

(3y - 1)^2 = 0

Step 2: Solve for y

3y - 1 + 1 = 0 + 1

3y / 3 = 1 / 3

y = 1/3

Answer: y = 1/3

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Answer-

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Solution-

The given function is,

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$\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50$

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lakkis [162]

Answer: Vertex (5 ,-9)

Step-by-step explanation:

Given : Function f(x) = (x – 8)(x – 2).

To find : What is the vertex of the quadratic function .

Solution : We have given that f(x) = (x – 8)(x – 2).

On removing parenthesis

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f(x) = x²-10x +16.

We need to find vertex of this function ,

Vertex: (h, k)

h = -.

Plugging values

h = -.

h = 5 this is the x- coordinate,

Now , we will plug x= 5 in quadratic function .

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Answer: the probability that the first toss wins is:

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Step-by-step explanation:

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For a pair of dice:

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The probability P of getting 7 is:

P = number of possible outcomes of 7/total number of possible outcomes

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Answer:

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Step-by-step explanation:

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