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3 years ago

9y^2-6y+1=0 FIND Y PLEASE HELP STEP BY STEP

Mathematics

1 answer:

dlinn [17]3 years ago

4 0

Answer:

y = 1/3

Step-by-step explanation:

<u>Step 1: Factor</u>

9y^2 - 6y + 1 = 0

(3y - 1)(3y - 1) = 0

(3y - 1)^2 = 0

<u>Step 2: Solve for y</u>

3y - 1 + 1 = 0 + 1

3y / 3 = 1 / 3

y = 1/3

Answer: y = 1/3

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Solve the polynomial inequation and graph the solution set on a number line. Express the solution in interval notation.

kirill [66]

Solving a polynomial inequation

Solving the following inequation:

(x - 8) (x + 1) > 0

We are going to find the sign both parts of the multiplication,

(x - 8) and (x + 1), have when

x < - 8

-8 < x < 1

1 < x

Then we know (x - 8) (x + 1) > 0 whenever (x - 8) (x + 1) is positive

We can see in the figure (x - 8) (x + 1) is positive when x < -8 and x > 1

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Answer:B

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1 year ago

To play basketball with her friends, Evangeline needs to pump air in her ball, which is completely deflated. Before inflating it

Nadya [2.5K]

Answer:

ρ_air = 0.15544 kg/m^3

Step-by-step explanation:

Solution:-

- The deflated ball ( no air ) initially weighs:

m1 = 0.615 kg

- The air is pumped into the ball and weight again. The new reading of the ball's weight is:

m2 = 0.624 kg

- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.

m_air = Δm = m2 - m1

m_air = 0.624 - 0.615

m_air = 0.009 kg

- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:

V_air = 4*π*r^3 / 3

V_air = 4*π*0.24^3 / 3

V_air = 0.05790 m^3

- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:

ρ_air = m_air / V_air

ρ_air = 0.009 / 0.05790

Answer: ρ_air = 0.15544 kg/m^3

4 0

2 years ago

Read 2 more answers

Do the ratios 20/10 and 1/2 form a proportion?

Tems11 [23]

Answer:

Yes . Divide by 10 for 10/20 to get 1/2.

10/10= 1

20/10= 2

10/20= 1/2

6 0

3 years ago

A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is

Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

$\Delta s = s_2-s_1$

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

$\Delta x = x_2-x_1$

So we can use the given points $P1:(x_1,y_2) \text{ and } P_2: (x_2,y_2)$ on the displacement formula

$\Delta x = 15-4\\\Delta x = 11$

In the same manner we can look at the y components of those points to find the vertical displacement

$\Delta y = 17-8\\\Delta y =9$

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

$\tan(\theta) = \cfrac{\Delta y}{\Delta x}$