ABCD ~ WXYZ. AD = 6, DC = 3, and WZ = 59. Find YZ.

Mathematics

1 answer:

dusya [7]3 years ago

5 0

You take alll the answers and just divide each one

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2x+5y=12

anastassius [24]

Y = -3x - 1......so we sub in -3x - 1 in for y in the other equation

2x + 5y = 12
2x + 5(-3x - 1) = 12....now distribute the 5 through the parenthesis
2x - 15x - 5 = 12...add 5 to both sides
2x - 15x = 12 + 5..combine like terms
-13x = 17...divide both sides by -13
x = -17/13
now sub in -17/13 for x in the other equation
y = -3x - 1
y = -3(-17/13) - 1
y = 51/13 - 1
y = 51/13 - 13/13
y = 38/13

so the solution is (-17/13, 38/13)

8 0

3 years ago

Greg's long jump measured 5 2/3 feet. Peter's long jump measured 6 3/4 feet. How many feet did the two boys jump altogether?

Len [333]

Answer:

12.41 or 12 5/12

Step-by-step explanation:

add 5.66+6.75=12.41

or 5 2/3 +6 3/4, get common denominator which is 12, then divide to get 5 8/12 +6 9/12= 11 17/12 or 12 5/12

5 0

2 years ago

List all the ways to select two members from S with repetition. The order in which the members are selected is not important. Fo

Taya2010 [7]

9514 1404 393

Answer:

KK KL KM KN KP LL LM LN LP MM MN MP NN NP PP

Step-by-step explanation:

Instead of starting with adjacent letters in the list, we start with the same letter. There are 15 possible pairs.

KK KL KM KN KP LL LM LN LP MM MN MP NN NP PP

<em>Additional comment</em>

We leave out pairs with letters previous, because you've said KL is the same as LK, and KL has already been listed. The problem with this list is that it misstates the probabilities of randomly obtaining a given pair. It is not 1/15, but is 2/25 for all but letter duplicates. For duplicates (KK), the probability is 1/25, not 1/15.

4 0

2 years ago

If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.

alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

$\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]$

The inverse of the matrix is

$\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]$

So, the Inverse Transformation is given by

$T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$