So,
The problem tells us that the length of the rectangle is 5 feet more than twice the width.
Mathematically:
length = 5 + 2width
l = 5 + 2w
We know that the perimeter is 2l + 2w.
2l + 2w = 130
2(5 + 2w) + 2w = 130
Distribute
10 + 4w + 2w = 130
Collect Like Terms
10 + 6w = 130
Subtract 10 from both sides
6w = 120
Divide both sides by 6
w = 20
The width is 20.
Since
l = 5 + 2w
Substitute
l = 5 + 2(20)
Multiply
l = 5 + 40
Collect Like Terms
l = 45
The length is 45.
Check
2l + 2w = 130
2(45) + 2(20) = 130
90 + 40 = 130
130 = 130
Width: 20 ft.
Length: 45 ft.
Answer:
3+7+11+15+(4n-1) = N(2n+1)
Step-by-step explanation:
atleast that's what i got-
Step-by-step explanation:
buena suerte con todo....
Answer:
y-int is -4 or (0,-4)
Step-by-step explanation:
That is the point where the line crosses the y-axis
Answer:
an = 7·2^(n-1)
a10 = 3584
Step-by-step explanation:
(a) The terms of the sequence do not have a common difference, but they do have a common ratio. That ratio is 14/7 = 2. The general term of a geometric sequence with first term a1 and common ratio r is ...
an = a1·r^(n-1)
For a1=7 and r=2, the explicit formula is ...
an = 7·2^(n-1)
__
(b) The 10th term is ...
a10 = 7·2^(10 -1) = 7·512
a10 = 3584
