X+2y = 9 ---------eq.1
x-y =6 ----------- eq.2
x = 9 -2y (from eq. 1)
Now substitute the value of x in the second eq.2
9-2y-y =6
-3y = -3
y =1
So,
x +2 (1)= 9
x= 7
The correct answer to this question is <span>d.) integral from 1 to 2 of (2/(x+1))
</span>To solve this:
Since Δx = 1/n.
lim (n→∞) Δx [1/(1+Δx) + 1/(1+2Δx)+ ... + 1/(1+nΔx)]
= lim (n→∞) Σ(k = 1 to n) [1/(1 + kΔx)] Δx.
x <---> a + kΔx
a = 0, then b = 1, so that Δx = (b - a)/n = 1/n
Since (1 + kΔx) combination, a = 1 so that b = 2.
Then, f(1 + kΔx) <-----> f(x) ==> f(x) = 1/x.
This sum represents the integral
∫(x = 1 to 2) (1/x) dx, so the correct answer is <span>d.) integral from 1 to 2 of (2/(x+1))
Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.
</span>
I can't see any table, is there a picture?
but something like 45x would be near the answer
Answer:x ≤ 3
Step-by-step explanation:
(14.5x − 5(x + 2) ≤ 4 + 4(4 − 1/8x)
14.5x - 5x-10 ≤ 4 + 16 - 1/2x Get rid of the parenthesis
9.5x-10 ≤ 20-1/2x Combine like terms
10x - 10 ≤ 20
10x/10 ≤ 30/10
x ≤ 3
Because all the sides are equal
