Answer:
Midpoint of side EF would be (-.5,4.5)
Step-by-step explanation:
We know that the coordinates of a mid-point C(e,f) of a line segment AB with vertices A(a,b) and B(c,d) is given by:
e=a+c/2,f=b+d/2
Here we have to find the mid-point of side EF.
E(-2,3) i.e. (a,b)=(2,3)
and F(1,6) i.e. (c,d)=(1,6)
Hence, the coordinate of midpoint of EF is:
e=-2+1/2, f=3+6/2
e=-1/2, f=9/2
e=.5, f=4.5
SO, the mid-point would be (-0.5,4.5)
An asexual structure where spores develop is Sporangium
Answer:
A. 2 in.
Step-by-step explanation:
Answer: $4.20
Step-by-step explanation:
Answer:
5a. 4w+24≤100
5b. Dimensions=31ft x 19 ft
Area = 589ft²
Step-by-step explanation:
l=w+12
p=2l+2w
p=2(w+12)+2w
p=2w+24+2w
p=4w+24
The farmer has 100ft of fencing, so maximum that the perimeter (p) can be is 100, meaning (4w+24) has to be less than or equal to 100:
4w+24≤100
For the largest possible perimeter, all 100 of fencing will be used, so allow 100 to be equal to 4w+24)
100=4w+24
4w=76
w=19ft
l=w+12
l=19+12
l=31ft
The dimensions are 31ft x 19ft.
Area=lw
=31*19
=589ft²
