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deff fn [24]
3 years ago
10

If L = 1/2(P - 2W), solve for p in terms of L and W (Show your work.) helpp im stuckk

Mathematics
2 answers:
skad [1K]3 years ago
8 0

Answer:

P = 2L + 2W

Step-by-step explanation:

L = ½ (P − 2W)

Multiply both sides by 2.

2L = P − 2W

Add 2W to both sides.

2L + 2W = P

Aloiza [94]3 years ago
7 0

Answer:P = 2L + 2W

Step-by-step explanation:

The given equation is expressed as

L = 1/2(P - 2W),

We want to solve for p in terms of L and W.

The first step would be to multiply the left hand side and the right hand side of the equation. It becomes

L × 2 = 1/2(P - 2W) × 2

2L = P - 2W

The next step would be to add 2W to the left hand side and the right hand side of the equation. It becomes

2L + 2W = P - 2W + 2W

P = 2L + 2W

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3 years ago
a small rocket is shot from the edge of a cliff suppose that after t seconds the rocket is y meters above the cliff where y=30t-
Natalka [10]

Answer:

Greatest height: 45 meters

Time for greatest height: 3 seconds

Height after 5 seconds: 25 meters above the cliff

Time for height of 40 meters: 7.123 seconds

Height after 7 seconds: -35 meters (35 meters below the cliff)

Step-by-step explanation:

to find the maximum height, we need to calculate the derivative of y in relation to t and then find when dy/dt = 0:

dy/dt = 30 - 10t = 0

10t = 30

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In this time, the height is:

y = 30*3 - 5*3^2 = 45 meters

After 5 seconds, the height is:

y = 30*5 - 5*5^2 = 25 meters

The time for the height of 40 meters is:

40 = 30t - 5t^2

t^2 - 6t - 8 = 0

Using Bhaskara's formula, we have:

Delta = 6^2 + 4*8 = 68

sqrt(Delta) = 8.246

t1 = (6 + 8.246) / 2 = 7.123 seconds

t2 = (6 - 8.246) / 2 = -1.123 seconds (negative value for time is not valid)

So the time when the rocket reaches 40 meters is 7.123 seconds

After 7 seconds, the height is:

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5 0
3 years ago
Can someone help me find the relative maximum and minimum? please i really need help
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Answer:

  • relative maximum: -4
  • relative (and absolute) minimum: -5

Step-by-step explanation:

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The relative maximum is -4.

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A relative minimum is a low point, where the curve is higher on either side. There are two of these, located symmetrically about the y-axis. The minimum appears to be about y = -5. (They might be at x = ± 1, but it is hard to tell.)

The relative minima are -5.

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A minimum or maximum is absolute if no part of the curve is lower or higher. Here, the minima are absolute, while the maximum is only relative. (The left and right branches of the curve go higher than y=-4.)

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Identifying the points on the curve should be the easy part. Deciding what the coordinates are can be harder when the graph is like this one.

4 0
2 years ago
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Answer:

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