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2 years ago

Can someone help me if they really know the answer pls!!

Mathematics

1 answer:

patriot [66]2 years ago

3 0

I’d say it’s around 405.58

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Can someone please answer this???? ASAP

timofeeve [1]

Answer:

A. $y=-\dfrac{8}{7}x-\dfrac{18}{7}$

Step-by-step explanation:

Let $y=mx+b$ be the equation of the perpendicular line.

Two perpendicular lines have slopes with product equal to -1. The slope of the given line is $\frac{7}{8}$ Hence,

$\dfrac{7}{8}\cdot m=-1\\ \\m=-\dfrac{8}{7}$

is the slope of needed line.

This line passes through the point (-4,2), so its coordinates satisfy the equation:

$2=-\dfrac{8}{7}\cdot (-4)+b\\ \\b=2-\dfrac{32}{7}=-\dfrac{18}{7}$

Therefore, the equation of the line is

$y=-\dfrac{8}{7}x-\dfrac{18}{7}$

7 0

2 years ago

What is 30.5% as a fraction in simplest form

QveST [7]

I believe that 30.5 as a fraction is 30 and 1 half but don't take my word

7 0

3 years ago

Is the sequence below is arithmetic {1, 8, 27,64}

Rzqust [24]

Answer:

Step-by-step explanation:

No, because 8 - 1 ≠ 27 - 8. So, there is no common difference which is needed in order for the sequence to be arithmetic

6 0

3 years ago

Simplify. (Assume all variables represent positive real numbers). Leave answer in radical form.

Flauer [41]

Answer:

$\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}$

Step-by-step explanation:

Given

$\sqrt{128a^{6}b^{13}}$

Required

Solve

$\sqrt{128a^{6}b^{13}}$

The expression can be split to:

$\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}$

So, we have:

$\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}$

$\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{3} * b^{6} * \sqrt{b}$

Rewrite as:

$\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2} * \sqrt{b}$

$\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}$

$\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}$

5 0

2 years ago

Find the slope between the points: (3,4) and (-1,-2)

pshichka [43]

Answer:

3/2 hope this helps hqhahjajja

8 0

2 years ago