The increasing order of the complex numbers is (√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.
<h3>
Absolute values of the complex numbers</h3>
The absolute values of the complex numbers are determined as follows;
(sqrt3-sqrt3i)^4 = (√3 - √3i)⁴

(-1+sqrt3i)^12 = (-1 + √3i)¹²

(sqrt 3-i)^6 = (√3 - i)⁶

(sqrt2-sqrt2i)^8 = (√2 - √2i)⁸

(sqrt2-i)^6 = (√2 - i)⁶

Increasing order of the complex numbers;
(√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.
Learn more about complex numbers here: brainly.com/question/10662770
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It's not clear to me what the given interval is supposed to be, so I'll use a generic one, [a, b] with a < b.
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Answer:
5, -1
Step-by-step explanation:
3x<10+8, 3x<18, x<6.