3 years ago

I'm really bored I don't know what to do

2 answers:

xeze [42]3 years ago

7 0

You should help me with my math hw

4 0

Answer:

neither do I, I'm also bored

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juin [17]

There are $\dbinom{|A|}k$ ways of building a subset of $k$ elements from $A$ , so the total number of subsets you can build is

$\displaystyle\sum_{k=0}^{|A|}\binom{|A|}k$

Recalling the binomial theorem, the above sum is equal to

$\displaystyle\sum_{k=0}^{|A|}\binom{|A|}k1^k1^{|A|-k}=(1+1)^{|A|}=2^{|A|}$

as required.

3 0

4 years ago

frez [133]

True, because the chord connect 2 points of the circumference, but radius connect the center and a point on the circumference.

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4 years ago

Aleks04 [339]

Hard question there bud

3 0

4 years ago

leonid [27]

Answer:

Step-by-step explanation:

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3 years ago

spin [16.1K]

Add nine to both sides then divide by 3 and K=4

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3 years ago

I'm really bored I don't know what to do​