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Lerok [7]
3 years ago
5

The radius of a circle is never a chord true or false

Mathematics
1 answer:
frez [133]3 years ago
8 0
True, because the chord connect 2 points of the circumference, but radius connect the center and a point on the circumference.
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A 32​-inch piece of steel is cut into three pieces so that the second piece is twice as long as the first​ piece, and the third
Goshia [24]

Answer:

first piece = 1.88in

second piece= 3.76in

third piece = 26.32in

32 = f + s + t

1st piece = f

2nd piece = s

3rd piece = t

what we know:

s = 2f

t = 2(7f)

32 = f + 2f + 2(7f)

32 = 3f +14f

32 = 17f

f = 1.88

now sub in:

f = 1.88

s = 3.76

t = 26.32

when you add these together you get 31.96, when you round up you get 32 which is the original piece of steel.

8 0
3 years ago
X^2-7x=0 solve the equation​
inn [45]

Answer:

x = 0, 7

Step-by-step explanation:

Step 1: Write out equation

x² - 7x = 0

Step 2: Factor out <em>x</em>

x(x - 7) = 0

Step 3: Find roots

x = 0

x - 7 = 0

x = 7

6 0
3 years ago
Read 2 more answers
Complete the paragraph proof. We are given that ∠B ≅ ∠C. Assume segment AB is not congruent to . If AB &gt; AC, then m∠C &gt; m∠
Lorico [155]

Given that ∠B ≅ ∠C.

to prove that the sides AB = AC

This can be done by the method of contradiction.  

If possible let AB \neq=AC

Then either AB>AC or AB<AC

Case i:  If AB>AC, then by triangle axiom, Angle C > angle B.

But since angle C = angle B, we get AB cannot be greater than AC

Case ii:  If AB<AC, then by triangle axiom, Angle C < angle B.

But since angle C = angle B, we get AB cannot be less than AC

Conclusion:

Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC

Hence if angle B = angle C it follows that

AB = AC, and AB ≅ AC.

6 0
2 years ago
Read 2 more answers
Type the correct answer in each box. The length of a rectangle is 2 inches more than its width. The perimeter of the rectangle i
vekshin1

Answer:

5 is the width and 7 is the length

4 0
2 years ago
Read 2 more answers
Find the sum: 2 + 9 + 16 + ... + 37
iris [78.8K]

Step-by-step explanation:

Sum of arithmetic terms = n/2 × [2a + (n - 1)×d], where 'a' is the first term, 'd' is the common difference between two numbers, and 'n' is the number of terms.

this is the same as n/2 × (a1 + an), because

an = a1 + (n-1)×d

so, for the series above :

a or a1 = 2

d = 7, as every new term is the previous term plus 7.

for n

37 = a1 + (n-1)×d = 2 + (n-1)×7

and now solve for n

35 = 7n - 7

42 = 7n

n = 6

so, the sum of all terms is

6/2 × (2+37) = 3×39 = 117

7 0
2 years ago
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