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Lerok [7]
4 years ago
5

The radius of a circle is never a chord true or false

Mathematics
1 answer:
frez [133]4 years ago
8 0
True, because the chord connect 2 points of the circumference, but radius connect the center and a point on the circumference.
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Write an equation. The local bike rental place charges $7 every hour a bike is rented and a $15 renters fee
dangina [55]

Answer:

y = 7x + 15

Step-by-step explanation:

total cost = $7 x every hour + $15 renters fee

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What does -m+8=4m-7<br>equal <br>​
Olegator [25]

Answer:

3

Step-by-step explanation:

-m+8=4m-7

8=4m-(-m)-7

8=4m+m-7

8=5m-7

5m=8+7

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Find LCM of:<br><br>x2 - 9, 3x3 + 81​
VikaD [51]

Answer:

\boxed{\pink{\sf (x + 3) \ is\ the \ LCM . }}

Step-by-step explanation:

Given two expressions ,

\qquad (1)\: x^2 - 9 \\\\ \qquad (2)\:3x^3 + 81

And , we need to find the LCM , that is lowest common factor . So , let's factorise them seperately .

<u>Factorising</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>9</u><u> </u><u>:</u><u>-</u><u> </u>

= x^2 - 9 \\\\= x^2 - 3^2 \\\\ \red{= (x+3)(x-3)} \qquad\bf [Using \ a^2-b^2 = (a+b)(a-b) ]

<u>Factorising</u><u> </u><u>3x</u><u>³</u><u> </u><u>+</u><u> </u><u>8</u><u>1</u><u> </u>

= 3x^3 + 81\\\\= 3(x^3+27) \\\\= 3( x^3+27) \\\\ = 3(x^3+3^3) \\\\ \red{= 3 [ (x+3)(x^2+9-3x) ] } \qquad \bf{[ Using \ a^3+b^3=(a+b)(a^2+b^2-ab) ] }

Hence we can see that (x+3) is common factor in both expressions.

<u>Hence</u><u> </u><u>the</u><u> </u><u>LCM</u><u> </u><u>is</u><u> </u><u>(</u><u> </u><u>x</u><u>+</u><u>3</u><u> </u><u>)</u><u> </u><u>.</u>

8 0
3 years ago
What is the sq root of 66666647362617?
PIT_PIT [208]

Answer:

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Step-by-step explanation:

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