Given that the image was dilated by scale factor 3 then:
a] Length of the dilated side will be:
length/width=(original length/width)*(scale factor)
length=3*10=30 in
Width=3*6=18 in
thus the dimensions of the new image will be:
30 in by 18 in
b. The diagram below represent s the rectangle. 1 cm represent 10 inches
Answer:
<em>x = -3 and y = 0</em>
Step-by-step explanation:
<em>It would be more direct to apply elimination in this problem, rather than substitution:</em>
2x + 6y = -6 ⇒ 2x + 6y = -6 ⇒ 10x = - 30
+ 2(4x - 3y = -12) + 8x - 6y = -24
<em>Now let us solve for x through simply algebra:</em>
10x = -30,
<em>x = -3</em>
<em>Substitute this value of x into the first equation to get the value of y:</em>
2( -3 ) + 6y = -6,
-6 + 6y = -6,
6y = 0,
<em>y = 0</em>
Answer:
Step-by-step explanation:
a+b+c=0, a+b=-c,a+c=-b, b+c=-a
(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=
a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=
a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=
a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=
a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=
6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=
2*[3abc-(a^3+b^3+c^3)]=0
so 3abc-(a^3+b^3+c^3)=0
so a^3+b^3+c^3=3abc
the word form of 485,830 is Four hundred eighty-five thousand eighty hundred thirty
Answer:
Acceleration=5m/s^2
Step-by-step explanation:
F=ma
1000=200xa
a=1000/200
a=5m/s^2
