Answer:
The answer is "0.36".
Step-by-step explanation:
we assume, that they are not blood-relatives, then we need both the dates (birth and death)
Births between 1512 and 2012 may occur at any time, and all of the math forms are what we have to be born at least 100 years apart.
Pr(Mathematician 1 is born inside an interval of 1512-2012 on a particular year)= )
Mathematician 2 born in 1512-2012 interval on every specific year) =
S Year of birth'
After that, We need to find all of the years of absolute value (birth the year Mathematician 1-birth year of Mathematician 2) <= 100 or give the probability of this happening.
Prob(Mathematician 1 birth between 1512-2012 in a specific group of 100 years):
For just a mathematician, are using the same rationale 2.
By using fact for freedom now Pr(that the dual births are divided by 100 years)) = 1-Pr(they are divided by more than 100 years):
8.1 x 10^-8
When going in the negative direction, the further left you go, the smaller the number.
These number would order smallest to largest as:
3.4x10^-10
9.2x10^-9
8.1x10^-8
8.2x10^-8
7.3x10^-5
Letters C & D
Answer:
-3 > -10
-7 > -8
2 > -9
Step-by-step explanation:
the comparison of the integers
Total amount for 36 months is $3049.20
The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are
<h3>How to determine the possible zeros?</h3>
The function is given as:
f(x) = 3x^6 + 4x^3 -2x^2 + 4
The leading coefficient of the function is:
p = 3
The constant term is
q = 4
Take the factors of the above terms
p = 1 and 3
q = 1, 2 and 4
The possible zeros are then calculated as:
So, we have:
Expand
Solve
Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are
Read more about rational root theorem at:
brainly.com/question/9353378
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