Answer:
Step-by-step explanation:
the tale-tell fellow is the number inside the parentheses.
if that number, the so-called "growth or decay factor", is less than 1, then is Decay, if it's more than 1, is Growth.
![\bf f(x)=0.001(1.77)^x\qquad \leftarrow \qquad \textit{1.77 is greater than 1, Growth} \\\\[-0.35em] ~\dotfill\\\\ f(x)=2(1.5)^{\frac{x}{2}}\qquad \leftarrow \qquad \textit{1.5 is greater than 1, Growth} \\\\[-0.35em] ~\dotfill\\\\ f(x)=5(0.5)^{-x}\implies f(x)=5\left( \cfrac{05}{10} \right)^{-x}\implies f(x)=5\left( \cfrac{1}{2} \right)^{-x} \\\\\\ f(x)=5\left( \cfrac{2}{1} \right)^{x}\implies f(x)=5(2)^x\qquad \leftarrow \qquad \textit{Growth} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20f%28x%29%3D0.001%281.77%29%5Ex%5Cqquad%20%5Cleftarrow%20%5Cqquad%20%5Ctextit%7B1.77%20is%20greater%20than%201%2C%20Growth%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20f%28x%29%3D2%281.5%29%5E%7B%5Cfrac%7Bx%7D%7B2%7D%7D%5Cqquad%20%5Cleftarrow%20%5Cqquad%20%5Ctextit%7B1.5%20is%20greater%20than%201%2C%20Growth%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20f%28x%29%3D5%280.5%29%5E%7B-x%7D%5Cimplies%20f%28x%29%3D5%5Cleft%28%20%5Ccfrac%7B05%7D%7B10%7D%20%5Cright%29%5E%7B-x%7D%5Cimplies%20f%28x%29%3D5%5Cleft%28%20%5Ccfrac%7B1%7D%7B2%7D%20%5Cright%29%5E%7B-x%7D%20%5C%5C%5C%5C%5C%5C%20f%28x%29%3D5%5Cleft%28%20%5Ccfrac%7B2%7D%7B1%7D%20%5Cright%29%5E%7Bx%7D%5Cimplies%20f%28x%29%3D5%282%29%5Ex%5Cqquad%20%5Cleftarrow%20%5Cqquad%20%5Ctextit%7BGrowth%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf f(t)=5e^{-t}\implies f(t)=5\left( \cfrac{e}{1} \right)^{-t}\implies f(t)=5\left( \cfrac{1}{e} \right)^t \\\\\\ \cfrac{1}{e}\qquad \leftarrow \qquad \textit{that's a fraction less than 1, Decay}](https://tex.z-dn.net/?f=%5Cbf%20f%28t%29%3D5e%5E%7B-t%7D%5Cimplies%20f%28t%29%3D5%5Cleft%28%20%5Ccfrac%7Be%7D%7B1%7D%20%5Cright%29%5E%7B-t%7D%5Cimplies%20f%28t%29%3D5%5Cleft%28%20%5Ccfrac%7B1%7D%7Be%7D%20%5Cright%29%5Et%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B1%7D%7Be%7D%5Cqquad%20%5Cleftarrow%20%5Cqquad%20%5Ctextit%7Bthat%27s%20a%20fraction%20less%20than%201%2C%20Decay%7D)
now, let's take a peek at the second set.
![\bf f(x)=3(1.7)^{x-2}\qquad \leftarrow \qquad \begin{array}{llll} \textit{the x-2 is simply a horizontal shift}\\\\ \textit{1.7 is more than 1, Growth} \end{array} \\\\[-0.35em] ~\dotfill\\\\ f(x)=3(1.7)^{-2x}\implies f(x)=3\left(\cfrac{17}{10}\right)^{-2x}\implies f(x)=3\left(\cfrac{10}{17}\right)^{2x} \\\\\\ \textit{that fraction is less than 1, Decay} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20f%28x%29%3D3%281.7%29%5E%7Bx-2%7D%5Cqquad%20%5Cleftarrow%20%5Cqquad%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Ctextit%7Bthe%20x-2%20is%20simply%20a%20horizontal%20shift%7D%5C%5C%5C%5C%20%5Ctextit%7B1.7%20is%20more%20than%201%2C%20Growth%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20f%28x%29%3D3%281.7%29%5E%7B-2x%7D%5Cimplies%20f%28x%29%3D3%5Cleft%28%5Ccfrac%7B17%7D%7B10%7D%5Cright%29%5E%7B-2x%7D%5Cimplies%20f%28x%29%3D3%5Cleft%28%5Ccfrac%7B10%7D%7B17%7D%5Cright%29%5E%7B2x%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Bthat%20fraction%20is%20less%20than%201%2C%20Decay%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf f(x)=3^5\left( \cfrac{1}{3} \right)^x\qquad \leftarrow \qquad \textit{that fraction is less than 1, Decay} \\\\[-0.35em] ~\dotfill\\\\ f(x)=3^5(2)^{-x}\implies f(x)=3^5\left( \cfrac{2}{1} \right)^{-x}\implies f(x)=3^5\left( \cfrac{1}{2} \right)^x \\\\\\ \textit{that fraction in the parentheses is less than 1, Decay}](https://tex.z-dn.net/?f=%5Cbf%20f%28x%29%3D3%5E5%5Cleft%28%20%5Ccfrac%7B1%7D%7B3%7D%20%5Cright%29%5Ex%5Cqquad%20%5Cleftarrow%20%5Cqquad%20%5Ctextit%7Bthat%20fraction%20is%20less%20than%201%2C%20Decay%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20f%28x%29%3D3%5E5%282%29%5E%7B-x%7D%5Cimplies%20f%28x%29%3D3%5E5%5Cleft%28%20%5Ccfrac%7B2%7D%7B1%7D%20%5Cright%29%5E%7B-x%7D%5Cimplies%20f%28x%29%3D3%5E5%5Cleft%28%20%5Ccfrac%7B1%7D%7B2%7D%20%5Cright%29%5Ex%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Bthat%20fraction%20in%20the%20parentheses%20is%20less%20than%201%2C%20Decay%7D)
Answer:
165 is the quotient
Step-by-step explanation:
3139 ÷ 19 = 165
(if you want the remainder it would be 4)
Answer: Choice B
Building A; it is around 50.34 feet taller than building B
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Explanation:
Draw two right triangles such that they both have a reference angle of 40 degrees. Since it's an angle of elevation, place the angle near the horizontal side.
Opposite each reference angle is the height of the building, which we'll call h.
The adjacent side is the horizontal distance from the person to the building.
Building A is 120 ft away so it's height is...
tan(angle) = opposite/adjacent
tan(40) = h/120
h = 120*tan(40)
h = 100.69
This value is approximate. Make sure your calculator is in degree mode.
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Repeat the same idea for building B, except the adjacent side is smaller this time.
tan(angle) = opposite/adjacent
tan(40) = h/60
h = 60*tan(40)
h = 50.35
This value is approximate.
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Now subtract the heights
100.69 - 50.35 = 50.34
This shows that building A is roughly 50.34 taller than building B.
Answer:
1
Step-by-step explanation: