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Agata [3.3K]
3 years ago
15

Eighth grade Find measures of complementary, supplementary, vertical, and adjacent angles what is the value of q?

Mathematics
1 answer:
Tatiana [17]3 years ago
3 0

Answer:

m\angle g=61^o

Step-by-step explanation:

we know that

If two angles are complementary then their sum is equal to 90 degrees.

In this problem

m\angle g+29^o=90^o -----> by complementary angles

subtract 29° both sides

m\angle g=90^o-29^o\\m\angle g=61^o

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Please answer number 1? Thank you
Naddik [55]

Answer:

This is a normal distribution and we can use the standard score to compute for probabilities. We compute the standard score of the given.

Explnation:

z = (x - mu)/sd

z = (2625 - 2600)/50 = 25/50 = 0.5.

Consulting the z-table, P(z <= 0.5) = 0.6915.

P(z > 0.5) = 1 - P(z <= 0.5) = 1 - 0.6915 = 0.3085.

I hope this helped! <3

6 0
3 years ago
Please help me on 7&amp;8 and please show your work :)
Llana [10]
7. 6/12 or 1/2 | 8. 5/12

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24 ÷ 21 with out any remainders​
shtirl [24]
24 divided by 21 is 1.14285714286. In fraction form it is 8/7, or 1 1/7.
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3 years ago
Read 2 more answers
Tisha and her academic team are working to go to state finals. They must have a certain number of points to advance. They have h
kolbaska11 [484]

Answer:

b=\frac{T-a-c-d}{3}

b = (T - a - c - d) / 3

Step-by-step explanation:

Let T be the total number of points required to advance.

a, c and d are points scored in the local matches, and b is the number of points scored in the district match. If b is worth 3 times as much as the other matches, the total number of points is given by:

T=a+c+d+3b

Isolate b in order to find out how many points they need in the district match:

T=a+c+d+3b\\3b=T-a-c-d\\b=\frac{T-a-c-d}{3}

They need to score (T - a - c - d)/3, in the district match in order to win.

4 0
3 years ago
15x-7=2+12x I need help with this
Amanda [17]

Answer:

\huge{ \boxed{ \bold{ \tt{x = 3}}}}

<h3>♁ Question : Solve for x</h3>
  • 15x - 7 = 2 + 12x

<h3>♁ Step - by - step explanation</h3>
  • \text{15x - 7 = 2 + 12x}

Move 12x to L.H.S ( Left Hand Side ) and change it's sign

➛\sf{15x - 12x - 7 = 2}

Move 7 to R.H.S ( Right Hand Side) and change it's sign

➛\sf{15x - 12x = 2 + 7}

Subtract 12x from 15x

Remember that only coefficients of like terms can be added or subtracted.

➛\sf{3x = 2 + 7}

Add the numbers : 2 and 7

➛\sf{3x = 9}

Divide both sides by 3

➛ \sf{ \frac{3x}{3}  =  \frac{9}{3}}

➛ \boxed{ \bold{ \sf{x = 3}}}

The value of x is \boxed{ \sf{3}}

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

☄ Now, let's check whether the value of x is 3 or not!

<h3>☥ Verification :</h3>

\sf{15x - 7 = 2 + 12x}

\dashrightarrow{ \sf{15 \times 3 - 7 = 2 + 12 \times 3}}

\dashrightarrow{ \sf{45 - 7 = 2 + 36}}

\dashrightarrow{ \sf{38 = 38}}

L.H.S = R.H.S ( Hence , the value of x is 3 ).

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

<h3>✒ Rules for solving an equation :</h3>
  • If an equation contains fractions ,multiply each term by the L.C.M of denominators.
  • Remove the brackets , if any.
  • Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their sign ' + ' into ' - ' and ' - ' into ' + ' .
  • Simplify and get the single term on each side.
  • Divide each side by the coefficient of variable and then get the value of variable.

Hope I helped!

Have a wonderful time ! ツ

~TheAnimeGirl

5 0
2 years ago
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