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lina2011 [118]
3 years ago
13

On a strange railway line, there is just one infinitely long track, so overtaking is impossible. Any time a train catches up to

the one in front of it, they link up to form a single train moving at the speed of the slower train. At first, there are three equally spaced trains, each moving at a different speed. You watch, and eventually (after all the linking that will happen has happened), you count the trains. You wonder what would have happened if the trains had started in a different order (but each of the original three trains had kept its same starting speed). On average (averaging over all possible orderings), how many trains will there be after a long time has elapsed? what if at the start there are 4 trains (all moving at different speeds)? or 5? or n?
SAT
1 answer:
hjlf3 years ago
6 0

On average The number of trains after a long time is = 2 trains

<u>Given data :</u>

Number of trains = 3

<u>Let's assume :</u>

speed of Train 1 = V₁

speed of Train 2 = V₂

speed of Train 3 = V₃

<h3> </h3><h3> Determine the number of trains after a long time has elapsed </h3>
  • Before linkage = 3 trains
  • When ( Train 1 and Train 2 links ) = 2 trains
  • When ( Train 1 , Train 2 and Train 3 links ) = 1 train
  • When ( Train 2 and Train 3 links ) = 2 trains

Therefore the average number of trains after a long time will be

( 3 + 2 + 1 + 2 ) / 4

= 8 / 4

= 2 trains

Hence we can conclude that On average The number of trains after a long time is = 2 trains

Learn more about Average calculations : brainly.com/question/20118982

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Let see if you know long division 3) 461​
WARRIOR [948]

Answer:

461 = dividend

3 = divisor

Explanation:

Step 1:

Start by setting it up with the divisor 3 on the left side and the dividend 461 on the right side like this:

           

   3 ⟌ 4 6 1

Step 2:

The divisor (3) goes into the first digit of the dividend (4), 1 time(s). Therefore, put 1 on top:

       1    

   3 ⟌ 4 6 1

Step 3:

Multiply the divisor by the result in the previous step (3 x 1 = 3) and write that answer below the dividend.

       1    

   3 ⟌ 4 6 1

      3    

Step 4:

Subtract the result in the previous step from the first digit of the dividend (4 - 3 = 1) and write the answer below.

       1    

   3 ⟌ 4 6 1

     - 3    

       1    

Step 5:

Move down the 2nd digit of the dividend (6) like this:

       1    

   3 ⟌ 4 6 1

     - 3    

       1 6  

Step 6:

The divisor (3) goes into the bottom number (16), 5 time(s). Therefore, put 5 on top:

       1 5  

   3 ⟌ 4 6 1

     - 3    

       1 6  

Step 7:

Multiply the divisor by the result in the previous step (3 x 5 = 15) and write that answer at the bottom:

       1 5  

   3 ⟌ 4 6 1

     - 3    

       1 6  

       1 5  

Step 8:

Subtract the result in the previous step from the number written above it. (16 - 15 = 1) and write the answer at the bottom.

       1 5  

   3 ⟌ 4 6 1

     - 3    

       1 6  

     - 1 5  

         1  

Step 9:

Move down the last digit of the dividend (1) like this:

       1 5  

   3 ⟌ 4 6 1

     - 3    

       1 6  

     - 1 5  

         1 1

Step 10:

The divisor (3) goes into the bottom number (11), 3 time(s). Therefore put 3 on top:

       1 5 3

   3 ⟌ 4 6 1

     - 3    

       1 6  

     - 1 5  

         1 1

Step 11:

Multiply the divisor by the result in the previous step (3 x 3 = 9) and write the answer at the bottom:

       1 5 3

   3 ⟌ 4 6 1

     - 3    

       1 6  

     - 1 5  

         1 1

           9

Step 12:

Subtract the result in the previous step from the number written above it. (11 - 9 = 2) and write the answer at the bottom.

       1 5 3

   3 ⟌ 4 6 1

     - 3    

       1 6  

     - 1 5  

         1 1

     -     9

           2

You are done, because there are no more digits to move down from the dividend.

The answer is the top number and the remainder is the bottom number.

Therefore, the answer to 461 divided by 3 calculated using Long Division is:

153

2 Remainder

8 0
3 years ago
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