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2 years ago

Find an equation for the line that passes through the points (-5, -5) and (3, 5)

Mathematics

1 answer:

Luda [366]2 years ago

8 0

Answer:

5x-4y+5=0.

Step-by-step explanation:

1) if the point A(-5;-5) and B(3;5), the formula is:

$\frac{x-X_A}{X_B-X_A} =\frac{y-Y_A}{Y_B-Y_A}$

2) according to the formula above:
$\frac{x+5}{3+5} =\frac{y+5}{5+5}; \ = > \ \frac{x+5}{4}=\frac{y+5}{5};$

or 5x-4y+5=0.

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Tammy wants to get change for $.30. The only coins she can get are quarters, nickels and dimes. How many different ways can she

Dmitry_Shevchenko [17]

1. One quater and one nicle 2. Three Dimes 3. 6 nickels 4. One dime and four nickles 5. two nickles and two dimes i think

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3 years ago

If m 2 n, which inequalities must be true? Check all that apply.

anzhelika [568]

Answer:

$(a)\ m+ 2.1 > n + 2.1$

$(b).\ m - (-4) > n - (-4)$

$(c)\ 9 +m> 6 + n$

Step-by-step explanation:

Given

$m > n$

Required

Select true inequalities

$(a)\ m+ 2.1 > n + 2.1$

Subtract 2.1 from both sides

$m > n$

This is true

$(b).\ m - (-4) > n - (-4)$

Open brackets

$m + 4 > n + 4$

Subtract 4 from both sides

$m > n$

$(c)\ 9 +m> 6 + n$

$m> -9+6 + n$

$m> n-3$

This is also true

8 0

3 years ago

Read 2 more answers

There is a pie-eating contest with 14 participants. There are 29 pies that are all eaten. Which of the following best describes

vitfil [10]

I don’t see any other way to say it except for 14/29

4 0

3 years ago

Heartbeat takes 0.8 seconds.how many seconds is this written as a fraction?

liubo4ka [24]

0.8 = 8/10

simplified = 4/5 seconds

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5 0

4 years ago

Read 2 more answers

Eric wants to get an output of 0. Can he do this with each machine? If so, how? If not, why not?

natita [175]

Answer:

No, he can get an output of 0 with the second machine (function B) but he cannot get an output of 0 with the first machine (function A).

Explanation

The way each machine works is given by the expression (function) inside it.

1) Function A

To get an output of 0 with the function y = x² + 3, you must solve the equation x² + 3 = 0.

Since x² is zero or positive for any real number, x² + 3 will never be less than 3 (the minimum value of x² + 3 is 3). So, it is not possible to get an output of 0 with the first machine.

2) Function B

Solve $y=\sqrt{x}-2=0$

$\sqrt{x}-2=0$

$\sqrt{x} =2$

$x=2^{2}$

$x=4$

So, he can get an output of 0 by using x = 4.

4 0

3 years ago