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Lynna [10]
2 years ago
14

Richard needed to read 5 books for his summer reading assignment. It took him 4 5/8 hours to read the first 2 books. It took him

7 7/8 hours to read the remaining 3 books. How long did it take Richard to read all 5 books?
A. 11 4/8 hours
B. 11 6/8 hours
C. 12 4/8 hours
D. 12 6/8 hours
Mathematics
2 answers:
zlopas [31]2 years ago
7 0
C.12 4/8 because 7+4=11 and 7/8+5/8= 1 4/8
Aleksandr-060686 [28]2 years ago
6 0

Answer: awnser d

Step-by-step explanation:

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La expecion del volumen​
Free_Kalibri [48]

Answer:

no hay imagen lo siento

Step-by-step explanation:

3 0
3 years ago
The distribution of the number of people in line at a grocery store has a mean of 3 and a variance of 9. A sample of the numbers
Airida [17]

Answer:

a) P(\bar X >4)=P(Z>\frac{4-3}{\frac{3}{\sqrt{50}}}=2.357)

P(Z>2.357)=1-P(Z

b) P(\bar X \frac{2.5-3}{\frac{3}{\sqrt{50}}}=-1.179)

P(Z

c)  

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

P(-1.179Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the number of people of a population, and for this case we know that:

Where \mu=3 and \sigma=\sqrt{9}=3

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X >4)= P(z> \frac{4-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z>2.357)=1-P(Z

Part b

P(\bar X  \frac{2.5-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z

Part c

For this case we want this probability:

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

And using a calculator, excel or the normal standard table we have that:

P(-1.179

7 0
3 years ago
12*10-50 i am in a hurry
andreev551 [17]

Answer: 70

Step-by-step explanation:

12*10 = 120-50 = 70

8 0
3 years ago
Aiden has one box that is 3 3/11 feet tall and a second box that is 3.27 feet tall. If he stacks the boxes, about how tall will
grandymaker [24]

Answer:

Step-by-step explanation:

8 0
3 years ago
Answer asap please !!
dangina [55]

Answer: C (21)


Step-by-step explanation:

I am translating into algebra.

Set Scott's age five years ago to: x

Set Paul's age five years ago to: 2x-4

Scott's age now is his age five years ago, plus five, which is: x+5

Paul's age now is his age five years ago, plus five, which is: 2x-4+5 or 2x+1

Since Paul is now six years older than Scott,  set Scott's age (x+5) equal to Paul's age, plus six, which is: 2x+1=x+5+6

Solve the equation to get: x=10

Substitute x for 10 in Paul's current age: 2*10+1=21.

Therefore, C is the correct answer.


5 0
3 years ago
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