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Diano4ka-milaya [45]
2 years ago
6

The probability that Maria succeeds at any given free-throw is 75%. She was curious how many free-throws she can expect to succe

ed in a sample of 10 free-throws. She simulated 25 samples of 10 free-throws where each free-throw had a 0.75 probability of being a success. Maria counted how many free-throws were successes in each simulated sample. Here are her results:​
Mathematics
1 answer:
Illusion [34]2 years ago
4 0

Answer:

5: 0 successes

6: 5 successes

7: 8 successes

8: 6 successes

9: 6 successes

10: 1 success

We need to use her results to estimate the probability that she succeeds at fewer than 7 free-throws in a sample of 10 free-throws.

First, find out how many successes were less than 7 (out of 25), which is 5.

now, we divide 5 by 25 (5/25, formula being number/total attempts) and simplify into a decimal, which comes out to 0.2

Probability w/ Venn Diagrams

Step-by-step explanation:

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To round off a given number in decimals to one decimal place (1 dp), we simply take the figure right after the decimal and approximate the remaining after it. If the second number after the decimal is a significant number (5 and above) we make it 1 and add to the number right after the decimal. If its NOT a significant number, we simply disregard it. The solutions therefore are;

ANSWER:

\begin{gathered} \text{Rounded to one decimal place;} \\ (1)0.698\%\approx0.7 \\ (2)53.123\%\approx53.1 \\ (3)0.075\%\approx0.1 \end{gathered}

Notice how the number in (1) becomes 0.7, after taking the next number (which is 9) and adding it as 1 to the number after the decimal (which is 6). The same applies to the number in (3).

\begin{gathered} (4)34.337\%\approx34.3 \\ (5)3.876\%\approx3.9 \end{gathered}

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Answer:

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Step-by-step explanation:

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