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Diano4ka-milaya [45]
2 years ago
6

The probability that Maria succeeds at any given free-throw is 75%. She was curious how many free-throws she can expect to succe

ed in a sample of 10 free-throws. She simulated 25 samples of 10 free-throws where each free-throw had a 0.75 probability of being a success. Maria counted how many free-throws were successes in each simulated sample. Here are her results:​
Mathematics
1 answer:
Illusion [34]2 years ago
4 0

Answer:

5: 0 successes

6: 5 successes

7: 8 successes

8: 6 successes

9: 6 successes

10: 1 success

We need to use her results to estimate the probability that she succeeds at fewer than 7 free-throws in a sample of 10 free-throws.

First, find out how many successes were less than 7 (out of 25), which is 5.

now, we divide 5 by 25 (5/25, formula being number/total attempts) and simplify into a decimal, which comes out to 0.2

Probability w/ Venn Diagrams

Step-by-step explanation:

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3 years ago
What are the solutions to this system of equations?
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A

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4 0
2 years ago
A countrys population in 1995 was 173 million in 1997 it was 178 million estamate the population in 2005 using the expontial gro
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199393207

Step-by-step explanation:

The formula for exponential growth which is expressed as

A = P(1 + r/n)^ nt

Where

A represents the population after t years.

n represents the periodic interval at which growth is recorded.

t represents the number of years.

P represents the initial population.

r represents rate of growth.

From the information given,

P = 173 million

A = 178 million

t = 1997 - 1995 = 2 years

n = 1

Therefore

178 × 10^6 = 173 × 10^6(1 + r/1)^2 × 1

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1.0289 = (1 + r)^2

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A = 173 × 10^6(1 + 0.0143)^10

A = 173 × 10^6(1.0143)^10

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4 0
3 years ago
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