Answer:
C. -7x^2 - 28
Step-by-step explanation:
Firstly simplify the bracket before doing anything;
4x(3x - 7) = 12x^2 - 28x
then go back to the question and substitute the expression(12x^2 - 28x) on the bracket and then work out the question;
12x^2 - 28x -19x^2...then group the values with the same exponent of x,
(12x^2 - 19x^2) - 28x
; -7x^2 - 28x
8-2 and then 3 divided by 6 which will give you 0.5 so x=0.5
Answer:
-30bc + 50bd
Step-by-step explanation:
3a + 5b/3c - 5d = 3a - 5b/3c - 5d
(3c - 5d)(3a - 5b) = (3a + 5b)(3c - 5d)
9ca - 15bc - 15da + 25db = 9ac - 15ad + 15bc - 25bd
9ca -15bc - 15da + 25db - 9ac + 15ad - 15bc + 25bd
9ca and -9ac and -15da and 15ad cancel each other out, so
-30bc + 50db is left
I can’t tell you a quotient unless there is a problem silly goose ...
goodluck , if you have the problem lmk
Answer:
6. <u> (2x - 1) </u>
(3x + 2)
8. <u> y - 3 </u>
y² - 3y + 9
Step-by-step explanation:
6. <u> 2x² + 9x - 5</u>
3x² + 17x + 10
= <u>(2x - 1) (x + 5)</u>
3x² + 17x + 10
= <u>(2x - 1) (x + 5)</u>
(3x + 2) (x + 5)
= <u> (2x - 1) </u>
(3x + 2)
8. <u>y² - 9 </u>
y³ + 27
= <u> (y + 3) (y - 3)</u>
y³ + 27
= <u> (y + 3) (y - 3) </u>
(y+3) (y² - 3y + 9)
= <u> y - 3 </u>
y² - 3y + 9
