Wyatt hiked 6 miles in 2 hours. At this same rate, what is the total number of miles Wyatt could hike in 9 hours?

2 answers:

5 0

If every 2 hours Wyatt hikes 6 miles, then every 9 hours Wyatt hikes 27 miles.
9÷2= 4.5 so...
6·4.5= 27
Your answer is 27.

stepan [7]3 years ago

4 0

Wyatt could hike for 27 miles in 9 hours. Hope this helped! PLS MARK BRAINLIEST!

You might be interested in

Write a polynomial function with the given zeros. multiply the terms (write in standard form).

ryzh [129]

$1) \ f(x)=x^3-3x-2 \\ \\ 2) \ g(x)=x^3-x^2-6x$

<h2>Explanation:</h2>

$A \ \mathbf{polynomial \ function} \ of \ x \ with \ degree \ n \ is \ given \ by:\\ \\ f(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\ldots +a_{2}x^{2}+a_{1}x+a_{0} \\ \\ where \ n \ is \ a \ nonnegative \ integer \ and \ a_{n}, a_{n-1}, \ldots a_{2}, a_{1}, a_{0} \\ with \ a_{n}\neq 0$

In this exercise, we have two cases and both will be polynomial functions with degree 3 because we have three real roots in each case. So:

<h3>First.</h3>

The roots are:

$x= -1, -1, 2$

So we can write this polynomial functions as the product of linear factors:

$f(x)=(x-(-1))(x-(-1))(x-2) \\ \\ f(x)=(x+1)^2(x-2)$

Since we have to write it in standard form, let's expand:

$f(x)=(x+1)^2(x-2) \\ \\ \\ By \ property: \\ \\ (a+b)^2=a^2+2ab+b^2 \\ \\ \\ f(x)=(x^2+2x+1)(x-2) \\ \\ f(x)=x^3+2x^2+x-2x^2-4x-2 \\ \\ \\ Combine \ like \ terms: \\ \\ x^3+(2x^2-2x^2)+(x-4x)-2 \\ \\ \\ \boxed{f(x)=x^3-3x-2}$

<h3>Second.</h3>

The roots are:

$x= -2, 0, 3$

Writing the polynomial function as the product of linear factors:

$g(x)=(x-(-2))(x-0)(x-3) \\ \\ g(x)=(x+2)x(x-3) \\ \\ g(x)=x(x+2)(x-3) \\ \\ \\ Distributive \property: \\ \\ g(x)=x(x^2-3x+2x-6) \\ \\ g(x)=x(x^2-x-6) \\ \\ \\ Distributive \ property \ again: \\ \\ \boxed{g(x)=x^3-x^2-6x}$

<h2>Learn more:</h2>

Degree of polynomial functions: brainly.com/question/5451252

#LearnWithBrainly

7 0

3 years ago

Read 2 more answers

A researcher has funds to buy enough computing power to number-crunch a problem in 5 years. Computing power per dollar doubles e

amm1812

A) In t months, the number of months required to number-crunch the problem will be
60*2^(-t/23)
By waiting t months, the researcher has made the total time f(t) to the solution of his problem be
f(t) = t + 60*2^(-t/23)

The derivative of this is
f'(t) = 1 + 60*ln(2)*(-1/23)*2^(-t/23)
We want to find the value of t that makes this be zero.
0 = 1 - 60*ln(2)/23*2^(-t/23)
2^(-t/23) = 23/(60*ln(2))
(-t/23)*ln(2) = ln(23/(60*ln(2)))
t = -23/ln(2)*ln(23/(60*ln(2))) ≈ 19.655

In order to finish his problem as soon as possible, the researcher should wait 19.7 months to buy his computers.

b) For this part of the problem, we want to find the value of "60" that makes t=0 be the solution. Taking the last expression and substituting t=0, 60=c, we get
0 = -23/ln(2)*ln(23/(c*ln(2)))
1 = 23/(c*ln(2)) . . . . . taking antilogs
c = 23/ln(2) ≈ 33.2

The largest value of c for which he should buy the computers immediately is 33.2.