Answer:
5:33. Simplified version: 1:6.6
Step-by-step explanation:
Hope this helps!
Answer:
6283 in³
Step-by-step explanation:
The largest sphere that can fit into the cardboard box must have its diameter, d equal to the length, L of the cardboard box.
Since the cardboard box is in the shape of a cube, its volume V = L³
So, L = ∛V
Since V = 12000 in³,
L = ∛(12000 in³)
L= 22.89 in
So, the volume of the sphere, V' = 4πr³/3 where r = radius of cube = L/2
So, V = 4π(L/2)³/3
= 4πL³/8 × 3
= πL³/2 × 3
= πL³/6
= πV/6
= π12000/6
= 2000π
= 6283.19 in³
≅ 6283.2 in³
= 6283 in³ to the nearest whole cubic inch
^n=1/square root of 59 (535) ,if that makes sense its hard to type it
Answer:
45 dollars
Step-by-step explanation:
Cosecant = hypotenuse / opposite side ( that is 1 / sine)
csc C = AC / 8
AC = sqrt (6^2 + 8^2) = sqrt 100 = 10
so cosecant of C is 10/8 = 1.25