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goblinko [34]
3 years ago
11

400 meters to 350 meters

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Minus 150 meters pepega I don’t quite understand the question but that is one way to get from 400 to 350 meters.

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Graham and Hunter are circus performers. A cable lifts Graham into the air at a constant speed of 1.5 ft/s. When Graham’s arms a
lidiya [134]

Answer: Hello there!

this type of equations in one dimension (when all the factors are constants) are written as:

h =  initial position +  initial velocity*t + (acceleration/2)*t^2

First, let's describe the hunter's equation:

We know that Graham moves with a velocity of 1.5 ft/s, and when he is  18 ft above the ground, Hunter throws the ball, and because Graham is pulled with a cable, he is not affected by gravity.

If we define t= 0 when Graham is 18 ft above the ground, the equation for Graham height (in feet) is:

h = 18 + 1.5t

where t in seconds.

Now, the equation for the ball:

We know that at t= 0, the ball is thrown from an initial distance of 5ft, with an initial velocity of 24ft/s and is affected by gravity acceleration g, where g is equal to: 32.2 ft/s (notice that the gravity pulls the ball downwards, so it will have a negative sign)

the equation for the ball is:

h = 5 + 24t - (32.2/2)t^2 = 5 + 24t - 16.1t^2

So the system is:

h = 18 + 1.5t

h = 5 +24t - 16.1t^2

so the right answer is A

5 0
3 years ago
Find x. Round to the nearest degree.
jeka94

The Law of Cosines features the 3 side lengths of a triangle, plus the measure of the angle opposite one of those sides.


We want angle x, which is opposite the side of length 39.


Then: a^2 = b^2 - 2ab cos C becomes 39^2 = 36^2 + 59^2 - 2(36)(59)cos x


or 1521 = 3481 + 1296 - 2(36)(59) cos x


Subtract (3481+1296) from both sides: 1521 - 4777 = -4248cos x

-3256 = -4248cos x

-3256

Then: cosx = --------------- = 0.766

-4248


Solving for x: x = arccos -0.766 = 0.698 radian, or 40 degrees (answer)

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3 years ago
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It has to do with slopes or something ​
Ostrovityanka [42]
What is it that I am supposed to be doing?
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2 years ago
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