Answer : The given polynomial equation can have 0,2 or 4 complex roots.
Explanation:-
Given polynomial equation is
which is a polynomial of degree 5.
We know that the complex roots always occur in pair ,therefore the number of complex roots in any polynomial must be an even number but less than equal to the degree of polynomial.
Thus, the given polynomial equation has 4 complex roots.
Answer:
18a + 12x - 12a + 15x
6a + 27x
the answer is a
Step-by-step explanation:
Answer:
Option B
Option E
Step-by-step explanation:
By the use of following postulates we can prove the two right triangles to be congruent.
1). HA - [Equal hypotenuse and an cute angles]
2). LL - [Two legs should be equal]
3). LA - [One leg and one angle must be equal]
4). ASA - [Two angles and the side containing these angles should be equal]
In the given right triangles,
1). OJ ≅ IL
2). ∠O ≅ ∠I
3). ∠J ≅ ∠L
Therefore, two postulates HA, ASA will be applicable for the congruence of the two triangles given.
Options A and E will be the answer.
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