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2 years ago

Hayden invested $750 for three years at an interest rate of 0.035. How much interest did he earn in that time?

Mathematics

1 answer:

Nadya [2.5K]2 years ago

5 0

Answer:

$78.75

Step-by-step explanation:

Principle: $750

Interest rate: 3.5%

Time: 3 years

750 x 3 x 3.5 % = $78.75

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Which Expression can be used to solve 3/5÷7/10A. 5/3*7/10B. 5/3*10/7C. 3/5*10/7D. 3/5*7/10

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A. 5/3*7/10

B. 5/3*10/7

C. 3/5*10/7

D. 3/5*7/10

This expression 3/5÷7/10 means

An option to solve the expression is inverting the fraction that is dividing and going to multiply

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Verification

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1 year ago

The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie

Fittoniya [83]

Answer:

The confidence interval is $25.16 < \mu < 26.85$

Step-by-step explanation:

From the question we are given a data set

25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

The mean of the this sample data is

$\= x = \frac{\sum x_i}{n}$

where is the sample size with values n = 10

$\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}$

$\= x = 26$

The standard deviation is evaluated as

$\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }$

substituting values

$= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }$

$\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }$

$\sigma = 1.625$

The confidence level is given as 90% hence the level of significance is calculated as

$\alpha = 100 -90$

$\alpha =10$ %

$\alpha = 0.10$

Now the critical values of $\frac{\alpha }{2}$ is obtained from the normal distribution table as

$Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining the critical values of $\frac{\alpha }{2}$ instead of $\alpha$ is because we are considering two tails of the area under the normal curve