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elena-s [515]
2 years ago
8

Find the value of x a:21 b:27 c:31 d:34

Mathematics
1 answer:
Oxana [17]2 years ago
4 0

Answer:

what's the problem?

Step-by-step explanation:

do u have a picture to show us?

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Find the slope of the line through the given pair of points, if possible. Based on the slope, indicate whether the line through
Sloan [31]

Answer:

Slope of line having points (3,-5) and (2,-2) is 3 and since the slope is positive do it rises. Option C is correct option.

Step-by-step explanation:

The formula calculate to find slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

We are given points (3,-5) and (2,-2) so,

x_1=3, y_1=-5, x_2=2, y_2=-2

Putting values in formula and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-2-(-5)}{2-3}\\Slope=\frac{-2+5}{1}\\Slope=3

So, Slope of line having points (3,-5) and (2,-2) is 3 and since the slope is positive do it rises. Option C is correct option.

7 0
3 years ago
Solve each system by elimination. 3x - 2y = 1 2x + 2 y = 14
Paha777 [63]
Add 3 and 12 , cancel -2 y+2y and and add 14 and 14
3x-2y=14
12x+2y=14
15x=28
Divide both sides by 15
X=28/15
3x 28/15 -2y=14
Y=-21/5
(X,y)=28/15, -21/5
3x 28/15 -2x(-21/5)=12x 28/15 +2x(-21/5)=14
14=14=14
(x, y)=(28/15, -21/5) is the answer
6 0
3 years ago
3/5 and 2/5<br> what is the common denomenator?
amid [387]

Answer:

5 is their common denominator

Step-by-step explanation:

A common denominator is when both denominators are the same.

5 0
3 years ago
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SIZIF [17.4K]

Answer:

ti is m(B{AC=70*

Step-by-step explanation:

8 0
3 years ago
Find the range, mean, and standard deviation of the data set (3, 6, 9, 11, 15, 16) The range is 13 (Type a whole number.) The me
iris [78.8K]

Answer: The range is 13.  The mean is 10. The standard deviation is 4.62 .

Step-by-step explanation:

The given data : 3, 6, 9, 11, 15, 16

Total number of data values : n = 6

The mean of data is given by :-

\overline{x}=\dfrac{\sum^6_{i=1}x_i}{n}\\\\\Rightarrow\overline{x}=\dfrac{60}{6}=10

The standard deviation is given by :-

\sqrt{\dfrac{1}{n}(\sum^6_{i=1}(x_i-\overline{x})^2)}\\\\=\sqrt{\dfrac{1}{6}(\sum^6_{i=1}(x_i-10)^2)}\\\\=\sqrt{\dfrac{1}{6}\times(49+16+1+1+25+36)}=4.61880215352\approx4.62

The range of the data : Maximum value -Minimum value

=16-3=13

6 0
3 years ago
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