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Ugo [173]
3 years ago
14

Which function does this graph represent? A. F(x) = 3(x 1)2 2 B. F(x) = -3(x 1)2 2 C. F(x) = -3(x 1)2 − 2 D. F(x) = 3(x − 1)2 2.

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

By analysing graph and then checking for all options we got that graph represent the function F(x) = -3(x +1)^2+ 2

<h3>What is function ?</h3>

Function is a relation from one set to another with a property that every element of a first set has a unique image in second set.

Here by looking at graph we can say that graph is if a quadratic equation

and it passes through (0,-1) and also from (-1,2)

Now we will check all options

(1)

Given function is

F(x) = 3(x +1)^2+ 2

Put x=0

F(0) = 3(0+1)^2+ 2=3+2=5

This function not passes through point (0,-1)

(2)

Given function is

F(x) = -3(x +1)^2+ 2

Put x=0

F(0) = -3(0+1)^2+ 2=-3+2=-1

Put x= -1

F(-1) = -3(-1 +1)^2+ 2=0+2=2

This function passes through both points (0,-1) and (-1,2)

(3)

Given function is

F(x) = -3(x +1)^2- 2

Put x= -1

F(-1) = -3(-1 +1)^2-2=0-2=-2

This function not passes through point (-1,2)

(4)

Given function is

F(x) = 3(x +1)^2+ 2

Put x=0

F(0) = 3(0+1)^2+ 2=3+2=5

This function not passes through point (0,-1)

By analysing graph and then checking for all options we got that graph represent the function F(x) = -3(x +1)^2+ 2

To learn more about function visit : brainly.com/question/25638609

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Two​ trains, Train A and Train​ B, weigh a total of 526 tons. Train A is heavier than Train B. The difference of their weights i
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Step-by-step explanation:

3 0
2 years ago
Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank
mars1129 [50]

Complete question:

Consider 3 boxes, each of which contains 4 balls in particular, box 1 contains 4 white balls, box 2 contains 3 white balls and 1 red ball, box 3 contains 2 white balls and 2 red balls. Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank extracts 2 balls with replacement. USE ONLY THE CONDITIONAL PROBABILITY FORMALISM and derive an expression for the probability that the 2 extracted balls are red.

Answer:

11/288

Step-by-step explanation:

We are given:

Box 1: ( 4White, ORed)

Box 2: (3White, 1Red)

Box 3: (2White, 2 Red)

We are told that if Frank choose from Box 1 and Box 3, 2 balls are extracted without replacement.

Since there is no red ball in Box 1, there is no way 2 red balls will come out from Box1.

Our Event, E = getting 2 red balls.

Now Box 1 is ruled out, we have:

P[E(B1)]= 0

P[E/B3)] = (2 2) / (4 2)

= 1/6

If box 2 is chosen, 2 balls are extracted with replacement. Therefore for Box 2:

P(E/B2) = (1/4) *(1/4)

= 1/16

Therefore probability that 2 balls extracted are red, we have:

P(E)=P(E/B1) P(B1) + P(E/B2) P(B2)+P(E/B3) P(B3)

= 0 * \frac{1}{3} + \frac{1}{6}*\frac{1}{3} + \frac{1}{16}*\frac{1}{3}

= 11/288

3 0
3 years ago
I need help please and thank you .i don't get get and i don't know if i got it right .
pshichka [43]

Answer: me so sorry come back later

Step-by-step explanation:

4 0
2 years ago
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How do you simplify this radical?<br><br> I can't seem to understand the steps
raketka [301]

Answer:

See the attachment.

Explanation:

6 0
2 years ago
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