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yuradex [85]
3 years ago
14

It took Amber 5 hours 16 minutes to finish a race. Her time at the halfway marker was 2 hours 49 minutes. How long did it take A

mber to complete the second half of the race?
-1 hour =?
-So, 5 hr 16 min = 4 hr ? Min?
-4 hour 76 min- 2 hr 49 min =?
Mathematics
2 answers:
KIM [24]3 years ago
8 0
3hr 33 min I guess not really sure
Ira Lisetskai [31]3 years ago
8 0
One hour=60 minutes
5 hours=300 minutes
2 hours=120 minutes
5 hours and 16 minutes=316 minutes
2 hours and 49 minutes=169 minutes
316 minutes-229 minutes=147 minutes
147 minutes=2 hours and 27 minutes
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Solve the equation below. Pls include work<br><br><br><br> 28.10 = 15.5 + 5x
madreJ [45]

Answer:

2.52

Step-by-step explanation:

5x + 15.5 = 28.1

subtract 15.5 from both sides

5x = 12.6

divide both sides by 5

x = 2.52

5 0
2 years ago
Read 2 more answers
What is the solution to the equation? 2x - 4 = 6
rusak2 [61]

Answer:

x = 5

Step-by-step explanation:

2x -4 = 6

Add +4 on both sides

2x = 10

Divide by 2

x = 5

6 0
3 years ago
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1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0
3 years ago
If varies inversely as . It is known that = 10 when = 3, find the value of when = 5.
Leto [7]

Answer:

y = 6

Step-by-step explanation:

If x varies inversely proportional as y.

x=\dfrac{k}{y}, k is constant of proportionality

or

k = xy

When x = 3 and y = 10

k = 3×10

k = 30

Put x = 5,

y=\dfrac{k}{x}\\\\y=\dfrac{30}{5}\\\\y=6

So, the value of y is 6 when x is 5.

8 0
2 years ago
How can you show that two objects are proportional with a table?
vredina [299]
So this is our table:

               -----------------
x-values | a b c d e f  |
               -----------------
y-values | g h  i  j k l   |
               -----------------

You can know that the values in the table are proportional if:

\frac{a}{g}=\frac{b}{h} =\frac{c}{i}=\frac{d}{j}=\frac{e}{k}=\frac{f}{l}

Hope that helps :)
5 0
3 years ago
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