Company A charges a $120 annual fee plus $7 per hour car share fee.
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Let x be the number of hours ling work on monday.
We know that she worked three more hours on tuesday that in monday, this can be express as :
We also know that in wednesday she worked on more hour than twice the number on mondays, this can be expressed as:
The total number of hours she worked this three days in two more than five the number of hours she worked on monday, this can be express as :
Now , once we have all the expressions we add the expressions of the days and equate them to the total
Now we solve the equation
Therefore , she worked 2 hours on monday.
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Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose
We have and
, because the dice are fair.
Now we use the assumption of independence to claim that
Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:
- 2 in a unique way (1+1)
- 3 in two possible ways (1+2, 2+1)
- 4 in three possible ways
- 5 in three possible ways
- 6 in three possible ways
- 7 in two possible ways
- 8 in a unique way
This implies that the probabilities of the outcomes of are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5
