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Ivenika [448]
2 years ago
8

Add= 38.42 and 7.1 please​

Mathematics
2 answers:
Dahasolnce [82]2 years ago
8 0

Answer:

45.52

Step-by-step explanation:

38.42 + 7 is 45.42, and 45.42 + 0.1 is 45.52

kramer2 years ago
3 0

Answer:

Let's look at the whole numbers first and put aside the decimals;

38 and 7, let's add these two: 38 + 7 = <u>45</u>

Now let's look at the decimals;

0.42 and 0.10, let's add these two:

<h3>   0 . 4 2</h3><h3>   0 . 1  0</h3>

+ _______

<h3>    0. 52 → Next, we add the decimals and the whole numbers:</h3>

45 + 0.52

<h2>= <u>45.52</u>, 45.52 is your answer.</h2>
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The answer is a because if you look at the first pair of numbers you'll get close amount so when you look at the second pair of numbers you will get 35.70 as an answer
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4 years ago
What is the value of x?
makkiz [27]

Answer:

106

Step-by-step explanation:

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7 0
3 years ago
Given AB= 20, BV=12, VA=14 and SR is a mid segment, find the given lengths
joja [24]

Given:

AB= 20, BV=12, VA=14 and SR is a mid segment.

To find:

The lengths of SR and AR.

Solution:

SR is a mid segment. So, SR is parallel to the non-included side BV and the length of SR is half of BV.

SR=\dfrac{1}{2}BV

SR=\dfrac{1}{2}(12)

SR=6

SR is a mid segment. So, it divides the included sides in two equal parts. It means R is the midpoint of VA.

AR=\dfrac{1}{2}VA

AR=\dfrac{1}{2}(14)

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Therefore, the measure of SR is 6 units and the measure of AR is 7 units.

8 0
3 years ago
Find the zeros in the function 3x2+ 6 = 0
sattari [20]

Answer:

x = ± i \sqrt{2}

Step-by-step explanation:

Given

3x² + 6 = 0 ( subtract 6 from both sides )

3x² = - 6 ( divide both sides by 3 )

x² = - 2 ( take the square root of both sides )

x = ± \sqrt{-2}

  = ± \sqrt{2(-1)}

  = ± (\sqrt{2} × \sqrt{-1}) → \sqrt{-1} = i

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5 0
4 years ago
Please Help<br> IMMEDIATELY
zmey [24]

Answer:

Let x equal the recurring decimal:

\sf Equation\:1: \quad x=0.216216216...

Create another number with recurring 216s by multiplying the above expression by 1000:

\sf Equation\:2: \quad 1000x=216.216216...

Subtract Equation 1 from Equation 2 to eliminate the recurring digits after the decimal:

\sf \implies 1000x-x=216.216216...-0.216216...

\sf \implies 999x=216

Divide both sides by 999:

\sf \implies \dfrac{999x}{999}=\dfrac{216}{999}

\sf \implies x=\dfrac{216}{999}

Simplify:

\sf \implies x=\dfrac{216 \div 27}{999 \div 27}=\dfrac{8}{37}

3 0
2 years ago
Read 2 more answers
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