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2 years ago

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Lisa bought a tank for her hermit crab. The tank can hold 1,331 cubic inches of water and includes a top. The base of the aquari

um is a square. The height of the aquarium is 11 inches. A: what is the length of each side of the base of the tank. B: what shape is Lisa’s tank. D what is the surface area of the tank

1 answer:

Alina [70]2 years ago

5 0

Answer:

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Step-by-step explanation:

<h2>event type motion detection event time you are you </h2>

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Keelah's clothing store bicycles for $50 and then sells them for $80 what is the percent of markup on the price of the coat

kondaur [170]

Answer:

62.5%

Step-by-step explanation:

We can write a proportion. We know that $50 is the original value and $80 is the marked up price. We don't know the marked up percentage. Let's call it x. We write equal ratios of $\frac{x}{100}$ comparing percent and $\frac{50}{80}$ comparing the 50 to the marked up price. We then set them equal.

$\frac{x}{100} =\frac{50}{80}$

We then cross multiply across the equal sign from numerator to the opposite numerator.

80(x)=50(100)

80x=5000

We divide to find x.

x=62.5

This means the bicycles are marked up 62.5% and the original value is 37.5%.

8 0

3 years ago

A juice drink filling machine, when in perfect adjustment, fills the bottles with 12 ounces of drink on an average. Any overfill

ozzi

Answer:

d. The average is equal to 12 ounces.

Step-by-step explanation:

In this problem, the drink filling machine must be perfectly calibrated at 12 ounces since it needs to be shut down in cases of overfilling (mean > 12 ounces) and underfilling (mean < 12 ounces). Therefore, the correct approach would be to test if the mean is 12 ounces and the correct set of hypothesis would be:

$H_0:\mu=12\\H_a:\mu\neq 12$

The correct alternative is d. The average is equal to 12 ounces.

5 0

3 years ago

Please help please help please help please help please help please help please help please help

german

Answer:

11x + y = 25

Step-by-step explanation:

Start with y = mx + b

Slope is -11, so m = -11

Point is (2, 3), so we plug that back in to get the intercept.

3 = -11 * 2 + b

3 = -22 + b

b = 25

y = -11x + 25

11x + y = 25 in standard form.

3 0

3 years ago

A conical cup is made from a circular piece of paper with radius 10 cm by cutting out a sector and joining the edges as shown be

SVEN [57.7K]

Part a:

The opening of the cup is the circular base of the cup which has a circumference equal to the length of the arc formed by angle <span>θ = 9π/5 on the circular piece of paper from which the cone was made.

Thus, the circumference of the circle = Length of the arc formed by angle </span>θ = 9π/5 at the center which is given by
$C=r\theta \\ \\ =10\times \frac{9\pi}{5} \\ \\ =18\pi\approx56.55\ cm$

Part b:
The opening of the cup is the circular base of the cup which has a circumference equal to the length of the arc formed by angle <span>θ = 9π/5 on the circular piece of paper from which the cone was made.

</span>Recall that the circumference of a circle is given by $C=2\pi r$ and having obtained from part a that the circumference of the circular opening is $18\pi$ cm.

Thus,
$2\pi r=18\pi \\ \\ \Rightarrow r=9\ cm$

Part c:
The height of the cup can be obtained by noticing that the radius, height and the slant height of the cup forms a right triangle with the height and the radius as the legs and the slant height as the hypothenus.

Using pythagoras theorem, the height of the cup is obtained as follows:
$h^2+r^2=l^2$
where: h is the height, r is the radius and l is the slant height.

$h^2+9^2=10^2 \\ \\ \Rightarrow h^2=100-81=19 \\ \\ \Rightarrow h= \sqrt{19} \approx4.36\ cm$

Part d
Recall that the volume of a cone is given by $V= \frac{1}{3} \pi r^2h$

Thus, the volume of the cup is given by
$V= \frac{1}{3} \pi\times9^2\times \sqrt{19} \\ \\ \approx369.7\ cm^3$

3 0

3 years ago

8^x=2<br> 8 to the power of x = 2. Find the value of x.

a_sh-v [17]

Answer:

$\huge{ \bold{ \boxed{ \sf{x = \frac{1}{3} }}}}$

☪ First , Let's know about Exponential Equation :

⤿ Let's take an equation : $\sf{ {2}^{x} = 8}$ .

In this equation , the variable ' x ' is the exponent of the base 2. Such an equation in which variable appears as an exponent of a base is known as exponential equation. The following axioms are useful while solving the exponential equations :

If $\sf{ {a}^{x} = {a}^{b} }$ , then $\sf{x = b}$
If $\sf{ {a}^{x} = 1}$ , then $\sf{ {a}^{x} = {a}^{0} }$ and x = 0

---------------------------------------------------------------

☯ Now , Let's Solve :

$\underline{ \sf{Given \: Exponential \: Equation \: : {8}^{x} = 2}}$

In this equation , the variable 'x' is the exponent of the base 8 .Write $\sf{ {8}^{x} }$ in exponential form with the base of 2

↦ $\sf{ {2}^{3x} = 2}$

Write the number 2 in exponential form with the base of 2.

↦ $\sf{ {2}^{3x} = {2}^{1}}$

Since the bases are same , cut 2 on both sides and set the exponents equal.

↦ $\sf{ { \cancel{2}} \: ^{3x} = { \cancel{2} } \: ^{1} }$

↦ $\sf{3x = 1}$

Divide both sides by 3

↦ $\sf{ \frac{3x}{3} = \frac{1}{3}}$

↦ $\boxed{ \bold{ \sf{x = \frac{1}{3} }}}$

And we're done!

Hope I helped!

Have a wonderful day! ツ

~TheAnimeGirl ♡

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5 0

3 years ago