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malfutka [58]
3 years ago
8

Quadrilateral ABCD with vertices A(0, 6), B(-3, -6), C(-9, -6), and D(-12, -3): a) dilation with scale factor of 1/3 centered at

the origin b) translation along the vector <-5,-1>
Mathematics
1 answer:
Oksanka [162]3 years ago
7 0

a) The points of the new quadrillateral are A'(x,y) = (0, 2), B'(x,y) = (-1, -2), C'(x,y) = \left(-3,-2\right) and D'(x,y) = (-4, -1), respectively.

b) The points of the new quadrillateral are A'(x,y) = (-5, 5), B'(x,y) = (-8,-7), C'(x,y) = (-13, -7) and D'(x,y) = (-17, -4), respectively.

<h3>How to perform transformations with points</h3>

a) A dillation centered at the origin is defined by following operation:

P'(x,y) = k\cdot P(x,y) (1)

Where:

  • P(x,y) - Original point
  • P'(x,y) - Dilated point.

If we know that k = \frac{1}{3}, A(x,y) = (0,6), B(x,y) = (-3,-6), C(x,y) = (-9, -6) and D(x,y) = (-12, -3), then the new points of the quadrilateral are:

A'(x,y) = \frac{1}{3}\cdot (0,6)

A'(x,y) = (0, 2)

B'(x,y) = \frac{1}{3} \cdot (-3,-6)

B'(x,y) = (-1, -2)

C'(x,y) = \frac{1}{3}\cdot (-9,-6)

C'(x,y) = \left(-3,-2\right)

D'(x,y) = \frac{1}{3}\cdot (-12,-3)

D'(x,y) = (-4, -1)

The points of the new quadrillateral are A'(x,y) = (0, 2), B'(x,y) = (-1, -2), C'(x,y) = \left(-3,-2\right) and D'(x,y) = (-4, -1), respectively. \blacksquare

b) A translation along a vector is defined by following operation:

P'(x,y) = P(x,y) +T(x,y) (2)

Where T(x,y) is the transformation vector.

If we know that T(x,y) = (-5,-1), A(x,y) = (0,6), B(x,y) = (-3,-6), C(x,y) = (-9, -6) and D(x,y) = (-12, -3),

A'(x,y) = (0,6) + (-5, -1)

A'(x,y) = (-5, 5)

B'(x,y) = (-3, -6) + (-5, -1)

B'(x,y) = (-8,-7)

C'(x,y) = (-9, -6) + (-5, -1)

C'(x,y) = (-13, -7)

D'(x,y) = (-12,-3)+(-5,-1)

D'(x,y) = (-17, -4)

The points of the new quadrillateral are A'(x,y) = (-5, 5), B'(x,y) = (-8,-7), C'(x,y) = (-13, -7) and D'(x,y) = (-17, -4), respectively. \blacksquare

To learn more on transformation rules, we kindly invite to check this verified question: brainly.com/question/4801277

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<h3>Further explanation</h3>

Follow the attached picture. I sincerely hope that's precisely a correct illustration.

We will use a graph of two intersecting straight lines.

Note that m ∠a and m ∠c are vertical angles. Since vertical angles share the same measures, in other words always congruent, we see \boxed{ \ m \ \angle{c} = m \ \angle{a} \ } \rightarrow \boxed{\boxed{ \ m \ \angle{c} = 47^0 \ }}

We continue to determine m ∠b and m ∠d.

Note that m ∠b and m ∠d represent supplementary angles. Recall that supplementary angles add up to 180°.

Let us see the following steps.  

\boxed{ \ m \ \angle{a} + m \ \angle{b} = 180^0. \ }

\boxed{ \ m \ 47^0 + m \ \angle{b} = 180^0. \ }

Both sides subtracted by 47°.

\boxed{ \ m \ \angle{b} = 180^0 - 47^0. \ }

Thus \boxed{\boxed{ \ m \ \angle{b} = 133^0. \ }}

Finally, note that m ∠b and m ∠d are vertical angles. Accordingly, \boxed{ \ m \ \angle{d} = m \ \angle{b} \ } \rightarrow \boxed{\boxed{ \ m \ \angle{d} = 133^0 \ }}

<u>Conclusion:</u>

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  • m ∠b = 133°
  • m ∠c = 47°
  • m ∠d = 133°

<u>Notes:</u>

  • Supplementary angles are two angles when they add up to 180°. \boxed{ \ example: \angle{a} + \angle{b} = 180^0 \ }
  • Vertical angles are the angles opposite each other when two lines cross. Note that vertical angles are always congruent, or of equal measure. \boxed{ \ example: \angle{a} = \angle{c} \ }
<h3>Learn more</h3>
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  2. Undefined terms needed to define angles  brainly.com/question/3717797
  3. Find out the measures of the two angles in a right triangle brainly.com/question/4302397

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