Either way. The probability of hitting the circle is:
P(C)=Area of circle divided by area of square
P(W)=(area of square minus area of circle divided by area of square
P(C)=(πr^2)/s^2
P(W)=(s^2-πr^2)/s^2
...
Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have:
P(inside circle)=π/121 (≈0.0259 or 2.6%)
P(outside circel)=(121-π)/121 (≈0.9744 or 97.4%)
1. y = 7
2. 0
3. m = -1
4. k = -4
5. x = -6
6. There is no solution for these equations.
Please let me know if you want explanations/work shown!! Hope this helps :)
Answer:
1094
Step-by-step explanation:
N = -1/10rt + 1/10q
= −14n+q+4n=rt−4n+4n
= −10n+q=rt
= −10n+q+−q=rt+−q
= −10n=rt−q
= -10n/-10 = rt-q/-10
So the answer is:
= n = -1/10rt + 1/10q
Answer:
A = pi 9/16 cm^2
Step-by-step explanation:
The circumference is 3/2 pi
The circumference is given by
C = 2 * pi *r
3/2 pi = 2 * pi *r
Divide each side by 2 *pi
3/2 pi / 2 pi = 2 pi r /2pi
3/4 cm = r
Now we can find the area
A = pi r^2
A = pi ( 3/4) ^2
A = pi 9/16 cm^2
