Using a 1-sample z-interval for the population proportion with confidence level 0.997, the sample probability is 0.69 with margin of error of 0.16, so between 0.69+0.16=0.85 of the population and 0.69-0.16=0.53 of the population prefers coffee. 84% and 54% are the correct answers.
Add the ratios together: 2 + 3 +4 = 9
Divide the total tips by 9:
77.40 / 9 = 8.60
Multiply each portion of the ratio by 8.60:
2 x 8.60 = 17.20
3 x 8.60 = 25.80
4 x 8.60 = 34.40
The ratios are in order of the people:
Paul got 17.20
Colin got 25.80
Brian got 34.40
Brian got 34.40 - 17.20 = 17.20 more than Paul
Answer:
The probability that a randomly selected chocolate bar will have a. Between 200 and 220 calories will be 0.3023
Step-by-step explanation:
Given:
True mean=225
S.D=10
X1=200 and X2=220
To Find:
P(X1<x<X2)
Solution:
<em>BY using Z-table for probability and Z-score we can proceed.</em>
So
For 200 calories Z will be ,
Z=(sample mean -true mean)/S.D
=200-225/10
=-25/10
=-2.5
For 220 calories Z will be ,
Z=220-225/10
=-5/10
=-0.5
So required probability will be




=0.3023