Answer:
(a) x = -2y
(c) 3x - 2y = 0
Step-by-step explanation:
You can tell if an equation is a direct variation equation if it can be written in the format y = kx.
Note that there is no addition and subtraction in this equation.
Let's put these equations in the form y = kx.
(a) x = -2y
- y = x/-2 → y = -1/2x
- This is equivalent to multiplying x by -1/2, so this is an example of direct variation.
(b) x + 2y = 12
- 2y = 12 - x
- y = 6 - 1/2x
- This is not in the form y = kx since we are adding 6 to -1/2x. Therefore, this is <u>NOT</u> an example of direct variation.
(c) 3x - 2y = 0
- -2y = -3x
- y = 3/2x
- This follows the format of y = kx, so it is an example of direct variation.
(d) 5x² + y = 0
- y = -5x²
- This is not in the form of y = kx, so it is <u>NOT</u> an example of direct variation.
(e) y = 0.3x + 1.6
- 1.6 is being added to 0.3x, so it is <u>NOT</u> an example of direct variation.
(f) y - 2 = x
- y = x + 2
- 2 is being added to x, so it is <u>NOT</u> an example of direct variation.
The following equations are examples of direct variation:
Answer:
Step-by-step explanation:
Solution
= -3/2
= 2
Answer:
Option A is right
Step-by-step explanation:
In any data set, we find that the range is the difference between maximum and minimum. The range cannot give full information about the variability of the data set.
Outliers are the ones which are either below Q1-1.5IQR or Q3+1.5IQR
Thus Inter quartile range, the difference between I quartile and III quartile gives a better idea about variability and also outlier.
Hence out of the four options given, we find that option B is the right one.
Option
A. The IQR is the best measure of variability because the distribution has an outlier.
The answer for this question is 1,100
