A^2 + 3b + c - 2d
(3)^2 + 3(8) + (2) - 2(5)
9 + 24 + 2 - 10 = 25
Answer:
58 units squared
Step-by-step explanation:
We want to find the area of the square. To do so, we need to find the hypotenuse of the right triangle because this coincides with the side length of the square.
We use the Pythagorean Theorem, which states that for a right triangle with legs a and b and hypotenuse c:
a^2 + b^2 = c^2
Here, a = 7 and b = 3, so:
7^2 + 3^2 = c^2
c^2 = 49 + 9 = 58
Now, the area of a square is: A = s^2, where s is the side length. Well, c is the side length, and we've already found what c^2 is (it's 58), so that means the area of the square is 58 units squared.
Thus, the answer is 58 units squared.
Answer:
What is your specific question regarding Pq?
Step-by-step explanation:
Verrrrrrry interesting ! / / / Every multiple of an even number is another even number. When you take any whole number and the one 'before' it ... no matter which direction 'before' means .... one of the numbers is even. So their product is a multiple of an even number, and it must be another even number.
7 unit to the left, means it is 7 less than -1.
-1-7 = -8
Ans: -8
