Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
Answer:
-134
Step-by-step explanation:
first, rewrite 54 as 6•9
next, rewrite 42 as 6•7
then, that gets you 6x^2 -6•7x- 6•9
lastly, factor out the common term (6)
and then you get 6(x^2-7x-9)
<u>please mark as brainliet <3</u>
Answer:
Option C is correct.
Equation of a line 
passing through (0,6) and (9,0).
Explanation:
Given the two points (0, 6) and (9 ,0).
To find the equation for the given two points 
and 
is,
; where m is the slope and is given by:
First find the slope m:
Substitute this value in equation of line:
or
⇒
Therefore, the equation for the given point is:
