Answer:
1/9
Step-by-step explanation:
Answer:
<em>The answer to your question is</em> <em>C.n ≥ 7</em>
Step-by-step explanation:
<u><em>I hope this helps and have a good day!</em></u>
The 3-digit number is 132
<h3>How to determine the
3-digit number?</h3>
The given parameters are:
- Number of digits = 3
- Sum of digits = 6
- No 0s in the number
- No repeated digit
The first highlight above implies that the number can be any of 100 to 999
The other highlights imply that the no digit can appear repeatedly, the highest digit in the number is 3, and the number must end with 2.
So, we have:
X32
The first digit is the smallest.
1 is smaller than 3 and 2.
So, we have
132
Hence, the 3-digit number is 132
Read more about digits and numbers at:
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The recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8
<h3>How to determine the recursive sequence that would produce the sequence?</h3>
The sequence is given as:
8,-35,137,…
From the above sequence, we can see that:
The next term is the product of the current term and -4 added to -3
i.e.
Next term = -3 + Current term * -4
So, we have:
T(n + 1) = -3 + T(n) * -4
Rewrite as:
T(n + 1) = -3 - 4T(n)
Hence, the recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8
Read more about recursive sequence at
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