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2 years ago

There is a spinner with 10 equal areas, numbered 1 through 10. If the spinner is spun

1 answer:

7 0

The probability that the result is a multiple of
2 and a multiple of 5 is; 0.1
We are told that:
-The spinner has 10 equal areas
- Numbers on the spinner are 1 to 10
Thus,
Total available numbers; N = 10 numbers
We want to find the probability that the result
is a multiple of both 2 and 5.
Now,among all the digits from 1 to 10, the
only one that is a multiple of both 2 and 5 is
10.
Thus,
P(result is a multiple of 2 and a multiple of 5)
= 1/10 = 0.1

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Let μ = 160 and σ = 16. find the z-score for the score, x = 150.

cricket20 [7]

Put the given values in the formula
$z=\dfrac{x-\mu}{\sigma}$
and evaluate.
z = (150 -160)/16 = -10/16
z = -5/8

The z-score for the score x=150 is -5/8 = -0.625.

8 0

3 years ago

Past records indicate that the probability of online retail orders

Tcecarenko [31]

Answer:

a) Mean = 1.6, standard deviation = 1.21

b) 18.87% probability that zero online retail orders will turn out to be fraudulent.

c) 32.82% probability that one online retail order will turn out to be fraudulent.

d) 48.31% probability that two or more online retail orders will turn out to be fraudulent.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The mean of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

In this problem, we have that:

$p = 0.08, n = 20$

a. What are the mean and standard deviation of the number of online retail orders that turn out to be fraudulent?

Mean

$E(X) = np = 20*0.08 = 1.6$

Standard deviation

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.08*0.92} = 1.21$

b. What is the probability that zero online retail orders will turn out to be fraudulent?

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.08)^{0}.(0.92)^{20} = 0.1887$

18.87% probability that zero online retail orders will turn out to be fraudulent.

c. What is the probability that one online retail order will turn out to be fraudulent?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{20,1}.(0.08)^{1}.(0.92)^{19} = 0.3282$

32.82% probability that one online retail order will turn out to be fraudulent.

d. What is the probability that two or more online retail orders will turn out to be fraudulent?

Either one or less is fraudulent, or two or more are. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 1) + P(X \geq 2) = 1$

We want $P(X \geq 2)$

$P(X \geq 2) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

From itens b and c

$P(X \leq 1) = 0.1887 + 0.3282 = 0.5169$

$P(X \geq 2) = 1 - P(X \leq 1) = 1 - 0.5169 = 0.4831$

48.31% probability that two or more online retail orders will turn out to be fraudulent.

4 0

4 years ago

177,178,179,180,190,200,210,211,212,213 why this pattern?

xz_007 [3.2K]

Because it is least to greatest

8 0

3 years ago

Read 2 more answers

Help plz it do tomorrow

Aneli [31]

The answer is D- 512

6 0

3 years ago

Divide. Write your answer as a decimal.<br><br> 0.459 divided by 0.17 =

Rudik [331]

Answer:

0.459 divided by 0.17 equals 2.7

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers