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-Dominant- [34]

2 years ago

5

Cos(x+2)=sin(3x). Need done for a test please help.

1 answer:

Ket [755]2 years ago

5 0

Can you specify the question please I can answer it but I need more specification 87

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If X=60, Y=25, and Z=65, what is the tangent of

LekaFEV [45]

Tangent is opposite/adjacent so it would 60/25 which simplifies to 12/5

8 0

3 years ago

Read 2 more answers

Identify the measure of arc PQ

Fudgin [204]

C, 62
Line segment SQ=180, because it is a straight line
90+28=118
180-118=62
hope this helps:)

7 0

3 years ago

Please answer number 2

viva [34]

They aren't necessarily equal because, for example, 3/2 = 1 remainder 1 and 5/4 = 1 remainder 1 aren't equal because it takes 2 x 1 = 2 + 1 = 3 while 4 x 1 = 4 + 1 = 5. They are the same quotient and remainer, except they aren't used to check if it multiplys back to the same divended.

8 0

3 years ago

Use the compound interest formulas A= P (1 + r/n) ^nt and A= Pe ^ rt to solve the problem given. Round to the nearest cent. Find

Dennis_Churaev [7]

Answer:

$\$30,460$
$\$30,497$
$\$30,522$
$\$30,535$

Step-by-step explanation:

We know that,

$A=P\left (1+\dfrac{r}{n}\right )^{n\cdot t}$

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

n = Number of times interest is compounded per year,

t = time period in year.

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded semiannually

Here,

P = $25,000

r = 5% = 0.05

n = 2 (as compounded semiannually)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{2}\right )^{2\times 4}$

$=25000\left (1+0.025\right )^{8}$

$=25000\left (1.025\right )^{8}$

$=\$30,460$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded quarterly.

Here,

P = $25,000

r = 5% = 0.05

n = 4 (as compounded quarterly)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{4}\right )^{4\times 4}$

$=25000\left (1+0.0125\right )^{16}$

$=25000\left (1.0125\right )^{8}$

$=\$30,497$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded monthly.

Here,

P = $25,000

r = 5% = 0.05

n = 12 (as compounded monthly)

t = 4 years

Putting the values,

$A=25000\left (1+\dfrac{0.05}{12}\right )^{12\times 4}$

$A=25000\left (1+\dfrac{0.05}{12}\right )^{48}$

$=\$30,522$

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded continuously.

$A= Pe^{rt}$

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

t = time period in year.

Putting all the values,

$A= 25000e^{0.05\times 4}=\$30,535$

It can be observed that, the frequent we compound the amount, the more we get.

7 0

3 years ago

PLEASE HELP Y’ALL

Lana71 [14]

Answer:

the answer is c 24 square meters

6 0

3 years ago