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2 years ago

Given u = (2, -8) and v = (8, -2), what is u times v?

1 answer:

jolli1 [7]2 years ago

3 0

Answer:

$u\cdot v=32$

Step-by-step explanation:

Assuming $u$ and $v$ are vectors, their dot product is $u\cdot v$ where $u_1v_1 + u_2v_2$ :

$u\cdot v=u_1v_1+u_2v_2=(2)(8)+(-8)(-2)=16+16=32$

Therefore, $u\cdot v=32$

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Original position of the submarine below the Surface = -2 2/3= -8/3

Submarine at a depth of -2 2/3 feet descended by 5 1/2 feet.

So new position of the Submarine = $\frac{-8}{3}-\frac{11}{2}\\\\ = \frac {-16 - 33}{2}\\\\ = \frac{-49}{6}$

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