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Consider this algebraic expression: –3x + x + 5 Use the algebra tiles to model the expression.

luda_lava [24]

For this case, we have the following expression:

$-3x + x + 5$

We simplify the expression:

If we add similar terms, taking into account that different signs are subtracted and the sign of the greater one is placed, we have that $-3x + x = -2x$

So, we have to:

$-3x + x + 5 = -2x + 5$

Answer:

-3x + x + 5 = -2x + 5

6 0

3 years ago

Read 2 more answers

Southern Oil Company produces two grades of gasoline: regular and premium. The profit contributions are $0.30 per gallon for reg

Contact [7]

Answer:

a) MAX--> PC (R,P) = 0,3R+ 0,5P

b) Optimal solution: 40.000 units of R and 10.000 of PC = $17.000

c) Slack variables: S3=1000, is the unattended demand of P, the others are 0, that means the restrictions are at the limit.

d) Binding Constaints:

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

Step-by-step explanation:

I will solve it using the graphic method:

First, we have to define the variables:

R : Regular Gasoline

P: Premium Gasoline

We also call:

PC: Profit contributions

A: Grade A crude oil

• R--> PC: $0,3 --> 0,3 A

• P--> PC: $0,5 --> 0,6 A

So the ecuation to maximize is:

MAX--> PC (R,P) = 0,3R+ 0,5P

The restrictions would be:

1. 18.000 A availabe (R=0,3 A ; P 0,6 A)

2. 50.000 capacity

3. Demand of P: No more than 20.000

4. Both P and R 0 or more.

Translated to formulas:

Answer d)

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

To know the optimal solution it is better to graph all the restrictions, once you have the graphic, the theory says that the solution is on one of the vertices.

So we define the vertices: (you can see on the graphic, or calculate them with the intersection of the ecuations)

V:(R;P)

• V1: (0;0)

• V2: (0; 20.000)

• V3: (20.000;20.000)

• V4: (40.000; 10.000)

• V5:(50.000;0)

We check each one in the profit ecuation:

MAX--> PC (R,P) = 0,3R+ 0,5P

• V1: 0

• V2: 10.000

• V3: 16.000

• V4: 17.000

• V5: 15.000

As we can see, the optimal solution is

V4: 40.000 units of regular and 10.000 of premium.

To have the slack variables you have to check in each restriction how much you have to add (or substract) to get to de exact (=) result.

3 0

2 years ago

O.9c + 1.89r = 17.01 c=18.9 - 2.1r equation answer

ikadub [295]

Answer:

$c=18.90-2.1r$

Step-by-step explanation:

The complete question is

A chef bought $17.01 worth of ribs and chicken. Ribs cost 1.89 per pound and chicken costs 0.90 per pound. The equation 0.90 +1.89r = 17.01 represents the relationship between the quantities in this situation.

Show that each of the following equations is equivalent to 0.9c + 1.89r = 17.01.

Then, explain when it might be helpful to write the equation in these forms.

a. c=18.9-2.1r. b. r= -10÷2c+9

we have that

The linear equation in standard form is

$0.90c+1.89r=17.01$

where

c is the pounds of chicken

r is the pounds of ribs

step 1

Solve the equation for c

That means ----> isolate the variable c

Subtract 1.89r both sides

$0.90c=17.01-1.89r$

Divide by 0.90 both sides

$c=(17.01-1.89r)/0.90$

Simplify

$c=18.90-2.1r$

step 2

Solve the equation for r

That means ----> isolate the variable r

Subtract 0.90c both sides

$1.89r=17.01-0.90c$

Divide by 1.89 both sides

$r=(17.01-0.90c)/1.89$

Simplify

$r=9-0.48c$

therefore

The equation $c=18.90-2.1r$ is equivalent

The equation is helpful, because if I want to know the number of pounds of chicken, I just need to substitute the number of pounds of ribs in the equation to get the result.

4 0

3 years ago

If the slope of y=2x+5 is changed to -2, how does the graph change?

Anon25 [30]

Don’t know can’t tell you

4 0

3 years ago

Classify the model as exponential growth or exponential decay. Identify the growth or decay factor AND the percent of increase o

MArishka [77]

See also brainly.com/question/8975313

The growth factor is 1.05.

The increase is (1.05 -1)*100% = 5% per period.

4 0

3 years ago