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3 years ago

8

Question is due soon I need help

1 answer:

lisov135 [29]3 years ago

8 0

Answer:

looks like C is best guess

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Find the distance between -48 and 17 on a number line.

Iteru [2.4K]

The distance is 65 because -48 plus 17 equals 65.

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3 years ago

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Omar buys stuffed animals for $4 each. He sells them for 7 each.<br> What is the percent profit?

love history [14]

I believe it is 75% because he is selling them for $3 more than what he bought them for and bought them for $4 and 3 is 75% of 4, sorry if i'm wrong

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3 years ago

Give the prime factorization of the number. use exponents when possible <br> 126

nataly862011 [7]

Answer:

=2*3^2 *7

Step-by-step explanation:

Prime factorization means to simplify 126 down to prime numbers

126 = 2*63

= 2* 9*7

= 2*3*3*7

Since 2 3 and 7 are prime numbers, we rewrite these with exponents

=2*3^2 *7

3 0

3 years ago

U-substitutions only work for specific kinds of expressions. Below, you are asked to choose a value of n for which u-substitutio

Dahasolnce [82]

Answer:

Step-by-step explanation:

(a) $\int x^n e^{5x^4+1} \ dx$

Suppose $5x^4 + 1 = f$

by differentiation;

$\implies \ 20 x^3 dx = df --- (1)$

Suppose n = 3

Then, the integral

$I = \int x^ 3 e^{5x^4 + 1} \ dx$

$= \int e^f \ \dfrac{df}{20}$

$= \dfrac{1}{20} \int e^f \ dt$

$= \dfrac{1}{20} e^f + C$

recall that $f = 5x^4 + 1$

Then;

$\mathbf{ I = \dfrac{1}{20}e^{5x^4+1}+C}$

(b) $\int \dfrac{cos (\dfrac{1}{x^3})}{x^n } \ dx$

suppose; $\dfrac{1}{x^3} = f$

$x^3 = f$

$\implies -3x^{-4} \ dx = df$

$\implies \dfrac{1}{x^4} \ dx =-\dfrac{1}{3} df$

If n = u, then the integration is:

$I = \int \dfrac{1}{x^4} \ cos (\dfrac{1}{x^4}) \ dx$

$= \int -\dfrac{1}{3} \ cos \ f \ df$

$= -\dfrac{1}{3} \int \ cos \ f \ df$

$= -\dfrac{1}{3} \ sin \ f + C$

Since; $x^3 = f$

Then;

$\mathbf {I = -\dfrac{1}{3} \ sin \ \Big( \dfrac{1}{x^3}\Big) + C}$

(c) $\int \dfrac{x+n}{x^2 + 8x -4} \ dx$

Suppose $x^2 + 8x - 4 = f$

Then, by differentiation of both sides

$(2x + 8) \ dx = df$

$(x + 4) \ dx = \dfrac{1}{2} \ df$

Suppose n = 4 in integration, then:

$I = \int \dfrac{(x + 4) }{x^2 +8x -4} \ dx$

By substitution;

$I = \int \dfrac{1}{2}\dfrac{1}{f} \ df$

$= \dfrac{1}{2} \ \ { In |f|} + C$

$\mathbf{= \dfrac{1}{2} \ \ { In |x^2+8x -4|} + C}$

7 0

3 years ago

Please help i'm taking a test, and when you get the answer please explain how you got it!!

Aleonysh [2.5K]

<u>Answer:</u>

y = 122.57

<u>Explanation:</u>

y = 143 when x = 49

Y varies directly with x, so the equation is --> y = kx (k would be the constant of variation).

k = y/x = 143/49

y = (143/49) x

When x = 42 --> y = (143/49) · 42 --> y = 2.92 · 42 --> y = 122.57

6 0

3 years ago