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Pepsi [2]
2 years ago
8

I’ll give brainliest pls do all 3

Mathematics
2 answers:
Phoenix [80]2 years ago
6 0

9:0.2

i will do 8 c7. 7 and 8 will take 30 min i will do ot now wait

fgiga [73]2 years ago
6 0

Answer:

Step-by-step explanation:

7.

Speed = Distance / time

Distance is fixed so speed x time = constant

speed1 x time1 = speed2 x time2

speed1/speed2 = time2/time1

speed1/speed2 = 20/27

time2/time1 = 20/27

Percentage decrease in time = (time1 - time2)/time1 x 100%

= (1 - time2/time1) x 100%

= (1 - 20/27) x 100%

= 7/27 x 100%

= 25.9%

8.

Let the equation of the angle bisector be y = mx + C

It is the angle bisector so its slope, m, is half way between slope of the two lines:

y = 2; slope = 0

y = 4x - 2; slope = 4

So m = (0 + 4) / 2 = 2

y = 2x + C

It is the angle bisector so the line must pass through intersection of the two lines:

y = 2 and y = 4x - 2

4x -2 = 2

x = 1

Intersection point is at x = 1 and y = 2

Substitute back into y = 2x + C

2 = 2(1) + C

C = 0

So the equation is y = 2x

9.

\sqrt{\frac{1}{25} } \\= \frac{\sqrt{1}}{\sqrt{25}} \\= \frac{1}{\sqrt{5^{2}}} \\\\

= 1/±5

= ±1/5

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Step-by-step explanation:

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Step 2 : f(-2)=3(x)-1

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3 years ago
Is x+y+1=0 a tangent of both y^2=4x and x^2=4y parabolas?
Lubov Fominskaja [6]

Answer:

  yes

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For the first parabola, the point of intersection is ...

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For the second parabola, the equation is the same, but with x and y interchanged:

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If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.

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