Answer:
At 12:18, eighteen minutes after noon, the number of bytes infected be the same in both computers.
Step-by-step explanation:
1. Lets name PC1 the first computer and PC2 the second computer, so, at noon 1 byte of PC1 is infected with the virus, that is:
PC1
Hour Bytes infected
12:00 1
Then, every minute thereafter, the number of bytes is multiplied by two, that is:
PC1
Hour Bytes infected
12:01 2
12:02 4
12:03 8
12:04 16
12:05 32
12:06 64
12:07 128
12:08 256
12:09 512
12:10 1024
12:11 2048
12:12 4096
2. In the minute 12 after noon, 1 byte of PC2 is infected, meanwhile PC1 has 4096 bytes infected as shown above, that is:
PC1 PC2
Hour Bytes infected Bytes infected
12:12 4096 1
And each minute thereafter, the number of bytes infected in PC2 multiplied by eight, that is:
PC1 PC2
Hour Bytes infected Bytes infected
12:13 8192 8
12:14 16384 64
12:15 32768 512
12:16 65536 4096
12:17 131072 32768
12:18 262144 262144
Therefore, at 12:18, eighteen minutes after noon the number of bytes infected be the same in both computers.
Answer:
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Step-by-step explanation:
Answer:
<POM=110°
I hope that's what you're looking for
D becaucause you have to do 12x8 and then 12x5 and whatever 12x8 is you but the answer bring down the + and do 12x5
Hi!
An obtuse angle is one greater than 90 degrees, a right angle one that is 90, and acute less than 90.
An obtuse triangle is one with one obtuse angle, all the rest being acute. A right triangle is one with one right angle, all the rest acute. And finally, an acute triangle is one with three acute angles.
In this case, the angles measure 83 degrees, 31 degrees, and 66 degrees. All of them are acute angles, as they're all less than 90 degrees.
Therefore, the triangle is an acute triangle.
Hope this helped!
