You use the formula below...,
Angle theta = cos^-1 [scalar product of the two vectors ÷ multiplication of their moduli]
For example...the angle between
(2i + 3j) and (4i + 5j)
Angle theta = cos^-1 [( 2(4) + 3(5))÷((square root of (2^2 + 3^2))×(square root of (4^2 + 5^2))
Angle theta = cos^-1 [ 23 ÷ ((square root of(13)) × (square root of (41)]
Angle theta = 5°
I think it is:
A = 9y = 3yx
A = 9y = 3y (3)
A = 9y = 9y
A = 9y
A/9 = y?
Answer:
10000
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that:
x + 4y = 30
x - 2y = 0
Subtracting both equations:
6y = 30
y = 30/6
y = 5
Putting in above equation
x + 4(5) = 30
x + 20 = 30
x = 10
i hope it will help you
