Answer:Let n = the smallest integer
Then the other integers are n+1, n+2, n+3 and n+4
Sum = n + n+1 + n+2 + n+3 + n+4 = 5n + 10 = 5(n + 2)
So the sum is always divisible by 5, for any value of n
Step-by-step explanation:
Answer:
x in terms of b = -3/b
x when b is 3 x = -1
15
