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Marina86 [1]
2 years ago
14

One number is one less than a second number. Twice the first is 10 more than 6 times the second. Find the numbers.

Mathematics
1 answer:
Zarrin [17]2 years ago
6 0

Answer:

  • The required numbers are <u>-3 and -4 </u>

Step-by-step explanation:

<u>Let's</u><u> assume</u><u>:</u><u> </u>

  • First number = x
  • Second number = y

<u>According to question</u>:

One number is one less than a second number.

  • x = y - 1 __(i)

Twice the first is 10 more than 6 times the second

  • 2x = 6y + 10 __ (ii)

<u>From </u><u>equation</u><u> (i) and (ii)</u>

➙2(y - 1) = 6y + 10

➙ 2y - 2 = 6y + 10

➙ 2y - 6y = 10 + 2

➙ -4y = 12

➙ -4/12 = y

➙ y = -3

<u>Substituting</u><u> </u><u>value </u><u>of </u><u> y in eq (i)</u>

➙ x = y - 1

➙ x = -3 - 1 = -4

Hence,

  • The required numbers are <u>-3 and -4</u>
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