Question

One number is one less than a second number. Twice the first is 10 more than 6 times the second. Find the numbers.

Answer 1

Answer:

• The required numbers are -3 and -4

Step-by-step explanation:

Let's assume:

• First number = x
• Second number = y

According to question:

One number is one less than a second number.

• x = y - 1 __(i)

Twice the first is 10 more than 6 times the second

• 2x = 6y + 10 __ (ii)

From equation (i) and (ii)

➙2(y - 1) = 6y + 10

➙ 2y - 2 = 6y + 10

➙ 2y - 6y = 10 + 2

➙ -4y = 12

➙ -4/12 = y

➙ y = -3

Substituting value of y in eq (i)

➙ x = y - 1

➙ x = -3 - 1 = -4

Hence,

• The required numbers are -3 and -4