One number is one less than a second number. Twice the first is 10 more than 6 times the second. Find the numbers.

Mathematics

1 answer:

Zarrin [17]2 years ago

6 0

Answer:

The required numbers are -3 and -4

Step-by-step explanation:

Let's assume: 

First number = x
Second number = y

According to question:

One number is one less than a second number.

x = y - 1 __(i)

Twice the first is 10 more than 6 times the second

2x = 6y + 10 __ (ii)

From equation (i) and (ii)

➙2(y - 1) = 6y + 10

➙ 2y - 2 = 6y + 10

➙ 2y - 6y = 10 + 2

➙ -4y = 12

➙ -4/12 = y

➙ y = -3

Substituting value of y in eq (i)

➙ x = y - 1

➙ x = -3 - 1 = -4

Hence,

The required numbers are -3 and -4

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