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4 years ago

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution.

Mathematics

2 answers:

Oksi-84 [34.3K]4 years ago

5 0

Answer:

Step-by-step explanation:

The answer is B hope this helps!

Nadya [2.5K]4 years ago

3 0

The answer is B

15 L of pure water must be mixed with 10 L of a 25% acid solution to reduce it to a 10% acid solution

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cupoosta [38]

Answer:

The last one: 25%

Step-by-step explanation:

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3 years ago

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WILL MARK YOU BRAINLIEST HELP WITH BOTH IF YOU CAN

Anna71 [15]

Answer:

10) 51°

11) 152

Step-by-step explanation:

10) 42 + 9 = 51

11) 45(3.5) + 22(-.25) = 157.5 - 5.5 = 152

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3 years ago

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What is 779,000,000 in scientific notation

DIA [1.3K]

Answer:

799 x 10^6

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Regularly it would be 799 x 1,000,000 so I converted it.

(\) QueTooOfficial (/)

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4 years ago

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3 years ago

Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumfer

almond37 [142]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

$\to \mu=\frac{\sum xi}{n}$

$=22.8$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187$

In point b:

$\to \mu=\frac{\sum xi}{n}$

$=20.6875$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251$

In point c:

$\to \mu=\frac{\sum xi}{n}$

$=21$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179$

In point d:

$\to \mu=\frac{\sum xi}{n}$

$=20.8375$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\ =\sqrt{0.553166667} \\\\ =0.7438$

6 0

3 years ago