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weeeeeb [17]
4 years ago
6

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution.

Mathematics
2 answers:
Oksi-84 [34.3K]4 years ago
5 0

Answer:


Step-by-step explanation:

The answer is B hope this helps!


Nadya [2.5K]4 years ago
3 0
The answer is B

15 L of pure water must be mixed with 10 L of a 25% acid solution to reduce it to a 10% acid solution
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Answer:

356.8cm3

Step-by-step explanation:

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marishachu [46]

Answer: w = 3.2

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