Question

(02.05 MC)

Answer 1

$\\ \rm\hookrightarrow x^2-6x+2$

$\\ \rm\hookrightarrow x^2-2(3)(x)+2$

$\\ \rm\hookrightarrow x^2-2(3x)+3^2-3^2+2$

• 3^2-3^2=0

$\\ \rm\hookrightarrow (x-3)^2-9+2$

$\\ \rm\hookrightarrow (x-3)^2-7$

Answer 2

Answer:

$f(x)=(x-3)^2-7$

Step-by-step explanation:

Use the formula:

$x^2+bx+c \implies (x+\frac{b}{2})^2-(\frac{b}{2}{)^2+c$

$f(x) = x^2 - 6x + 2$

$\implies f(x)=(x-\frac62)^2-(\frac62)^2+2$

$\implies f(x)=(x-3)^2-3^2+2$

$\implies f(x)=(x-3)^2-9+2$

$\implies f(x)=(x-3)^2-7$