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2 years ago

HELP!!! I need someone to answer this question quick

Mathematics

1 answer:

Sav [38]2 years ago

6 0

the volume of the ball is 523.3. since the formula for the volume is 4/3*pi*r^3, the radius of ball is 5 in. Therefore, the diameter of the ball and the height of the box is 10.

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Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0

3 years ago

What is an equation of the line that passes through the points (0, 3) and (5,−3)?

g100num [7]

Answer:

y = -6/5x + 3

Step-by-step explanation:

y = mx + c (or b, depending on where you're from)

Slope = m = -6/5

y = -6/5x + c

You can sub (0, 3) and (5, -3) into y = -6/5x + c and they both have the same answer where c = 3

Therefore, the equation is y = -6/5x + 3

Hop this helps

5 0

2 years ago

HELP ME ASAP PLEASE!!

Daniel [21]

Answer:

set both of them equal to each other:

8x - 8° = 5x + 25°

subtract 5x by both sides of the equations and it becomes:

3x-8° = 25°

now add 8° both sides:

3x = 33°

divide three by both sides:

x = 11°

now thats done to find B:

plug your x value in the B equation:

5x + 25°

5(11) +25°

55 +25°

not sure if you can add here sorry :(. I hope this helped so far :)

5 0

2 years ago

Six sets of eight objects each

puteri [66]

Answer:

6 × 8 = 48

Step-by-step explanation:

6 sets of 8 objects, to get the answer you have to multiply

6×8 = 48

7 0

2 years ago

A merchant sold a pen for $6.90 ,thereby making a profit of 15% on her cost calculate the cost of the pen to the merchant to the

NeTakaya

So you know the merchant made a 15% profit on the pen, so she bought it for a cheaper price. To find the cost of the pen before you have to take the price now, $6.90 and times it by 85%. You do 85% because you subtract the 15% she saved from 100% and you get 85%. So 6.90x.85= 5.865 which rounds to $5.87

7 0

3 years ago